All categories

3 years ago

Desde que altura debes de lanzar una canica de 50g para que adquiera una energia de 100j

Physics

1 answer:

AnnZ [28]3 years ago

7 0

Answer:

204 m

Explanation:

When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

$\Delta U=mg\Delta h$

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

$\Delta h$ is the change in height

In this problem, we have

m = 50 g = 0.05 kg

$\Delta U = 100 J$

Solving the formula for $\Delta h$ , we find the necessary height from which the marble should be dropped:

$\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m$

You might be interested in

Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.0095 m

PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A

Explanation:

We have given number of turns in inner coil $N_I=170$

Radius of inner circle $r_i=0.0095m$

Current in the inner circle $I_i=8.9A$

Number of turns in outer circle $N_o=150$

Radius of outer circle $r_o=0.015m$

We have to find the current in outer circle so that net magnetic field will zero

For net magnetic field current must be in opposite direction as in inner circle

We know that magnetic field is given due to circular coil is given by

$B=\frac{N\mu _0I}{2r}$

For net magnetic field zero

$\frac{N_I\mu _0I_I}{2r_I}=\frac{N_O\mu _0I_0}{2r_O}$

So $\frac{170\times \mu _0\times 8.9}{2\times 0.0095}=\frac{150\times \mu _0I_O}{2\times 0.015}$

$I_O=15.92A$

4 0

3 years ago

Usimov [2.4K]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

Why are simple everyday actions considered

Oxana [17]

They create energy ……………….

8 0

3 years ago

Read 2 more answers

help me pass the test please there is a couple of questions in my profile to answer i am leaving this one for you to help

kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

6 0

2 years ago

Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N,

White raven [17]

The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

Force applied to the right (Fᵣ) = 250 N
Force applied to the left (Fₗ) = 315 N
Net force (Fₙ) =?

The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

Therefore, the net force acting on the car is 65 N to the left

Learn more on net force: brainly.com/question/19549734

8 0

2 years ago

Read 2 more answers