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2 years ago

Desde que altura debes de lanzar una canica de 50g para que adquiera una energia de 100j

Physics

1 answer:

AnnZ [28]2 years ago

7 0

Answer:

204 m

Explanation:

When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

$\Delta U=mg\Delta h$

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

$\Delta h$ is the change in height

In this problem, we have

m = 50 g = 0.05 kg

$\Delta U = 100 J$

Solving the formula for $\Delta h$ , we find the necessary height from which the marble should be dropped:

$\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m$

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1 year ago

A flat disk of radius 0.50 m is oriented so that the plane of the disk makes an angle of 30 degrees with a uniform electric fiel

nexus9112 [7]

Answer:

The electric flux is $280\ \rm N.m^2/C$

Explanation:

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$\phi=\int E.dA$

where

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Now according to question we have

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3 years ago

How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to

finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is $x=\sqrt{\frac{2\times EPE}{k}}$

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

$EPE=\frac{1}{2}kx^2$

Rewriting the above expression in terms of 'x', we get:

$x=\sqrt{\frac{2\times EPE}{k}}$

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

$x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m$

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

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2 years ago