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melomori [17]
3 years ago
8

A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)

Physics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

<h2>\boxed{  \bold{ \purple{0.0769 \: kg \: }}}</h2>

Explanation:

\sf{Potential   Energy ( P.E ) \:  =  \: 20.8 \: joule}

\sf{distance \:  = 27.6 \: metre}

\sf{mass = } ?

\sf{acceleration \: due \: to \: gravity = 9.68 \:  {metre \: per \: second}^{2} }

Now, let's find the mass:

\sf{PE  \:  =  mass \times gravity \:  \times  \: distance}

plug the values

⇒\sf{20.8 = m \times 9.8 \times 27.6}

Multiply the numbers

⇒\sf{20.8 = 270.48 \: m}

Swap the sides of the equation

⇒\sf{270.48m = 20.8}

Divide both sides of the equation by 270.48

⇒\sf{ \frac{270.48m}{270.48}  =  \frac{20.8}{270.48} }

Calculate

⇒\sf{0.0769} kg

Hope I helped!

Best regards!!

lora16 [44]3 years ago
6 0

Answer:

\huge \boxed{\mathrm{0.0769 \ kg}}

Explanation:

\displaystyle \sf Mass=\frac{Potential \ energy}{Acceleration \ of \ gravity \times Height}

\displaystyle m=\frac{PE}{gh}

\mathrm{We \ need \ to \ find \ the \ mass.}

\displaystyle m=\frac{20.8}{9.8 \times 27.6}

m= 0.0769

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<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

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Rearranging

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\theta=53.13^o

4 0
3 years ago
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