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diamong [38]
3 years ago
13

A 970 kg car starts from rest on a horizontal roadway and accelerates eastward for 5 s when it reaches a speed of 25 m/s. What i

s the average force exerted on the car during this time
Physics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

i hounestly dont know

Explanation:

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At sunrise two old women started to walk towards each other. one started from point a and went towards point b while the other s
konstantin123 [22]

Let the distance between points a and b = d

For the women starting from a her velocity be V_1 and for the women starting from b her velocity be V_2

Let the rising time of sun = x AM

We have  V_1 = \frac{d}{12+4-x}

and we also have  V_2 = \frac{d}{12+9-x}

At they meet means, they both travel a combined distance of d

So we have   V_1*(12-x)+V_2*(12-x)=d

Substituting velocity values we will get

  \frac{d}{12+4-x}*(12-x)+\frac{d}{12+9-x}*(12-x)=d\\ \\ \frac{12-x}{12+4-x}+\frac{12-x}{12+9-x}=1\\ \\ \frac{12-x}{16-x}+\frac{12-x}{21-x}=1\\ \\ 252-21x-12x+x^2+192-12x-16x+x^2=336-16x-21x+x^2\\ \\ x^2-24x+108=0\\ \\ (x-6)(x-18)=0\\ \\

 x= 6 AM or 18 AM, but 18 AM is not possible,

Sun rise time is 6 AM


3 0
3 years ago
Darren drives to school in rush hour traffic and averages 28 mph. He returns home in mid-afternoon when there is less traffic an
Gala2k [10]

Answer:

distance between school and home is 21 miles

Explanation:

given data

in rush hour speed  s1 = 28 mph

less traffic speed s2 = 42 mph

time t = 1 hr 15 min = 1.25 hr

to find out

distance  d

solution

we consider here distance home to school is d and t1 time to reach at school

we get here distance equation when we go home to school that is

distance = 28 × t1    .......................1

and when we go school to home distance will be

distance = 42 × ( t - t1 )

distance = 42 × ( 1.25 - t1 )     ...................2

so from equation 1 and 2

28 × t1 = 42 × ( 1.25 - t1 )

t1 = 0.75

so

from equation 1

distance = 28 × t1

distance = 28 × 0.75

distance = 21 miles

4 0
3 years ago
Electrically charged sunspot gases which escape the sun's chromosphere and enter the earth's atmosphere near the magnetic north
Kisachek [45]

Answer:

Northern Lights ( Aurora Borealis)

Explanation:

When the electricaly charged sunspot gases (they are named a solar wind) escape the sun's chromosphere and penetrates from the earth magnetic sheild which is called earth's magnetosphere then upon there interaction with atoms and molecules of our atmosphere there are little bursts of photons in the form of light which made up these northern lights.

6 0
3 years ago
An ideal spring has spring constant ks (to distinguish it from the electrostatic constant k) and equilibrium length l. Then, you
nexus9112 [7]

Answer:

q = square root (4KsL³/k)

The force of extension of the spring is equal to the force of repulsion between the two like charges. Two like charges(positive or negative) would always repel each other and two unlike charges would always attract each other. This electric force between the charges is what is responsible for the stretching of the spring. The electric force causes the spring to increase in length from L to 2L. Equating these forces, that is the electric force between the charges and the elastic force of the spring and rearranging the variables gives the expression to obtain q.

Explanation:

See the attachment below for full solution.

5 0
4 years ago
Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71
kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

  • Mass of the rope, m = 71 kg
  • Tension on the rope, T = 220 N
  • Coefficient of kinetic friction, = 0.1
  • Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>
  • Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\  0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

7 0
3 years ago
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