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777dan777 [17]
3 years ago
9

An earthquake emits both S-waves and P-waves which travel at different speeds through the Earth. A P-wave travels at 9 000 m/s a

nd an S-wave travels at 5 000 m/s. If P-waves are received at a seismic station 1.00 minute before an S-wave arrives, how far away is the earthquake center?
Physics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Assuming constant speeds, the P-wave covers a distance <em>d</em> in time <em>t</em> such that

9000 m/s = <em>d</em>/(60 <em>t</em>)

while the S-wave covers the same distance after 1 more minute so that

5000 m/s = <em>d</em>/(60(<em>t</em> + 1))

Now,

<em>d</em> = 540,000 <em>t</em>

<em>d</em> = 300,000(<em>t</em> + 1) = 300,000 <em>t</em> + 300,000

Solve for <em>t</em> in the first equation and substitute it into the second equation, then solve for <em>d</em> :

<em>t</em> = <em>d</em>/540,000

<em>d</em> = 300,000/540,000 <em>d</em> + 300,000

4/9 <em>d</em> = 300,000

<em>d</em> = 675,000

So the earthquake center is 675,000 m away from the seismic station.

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Explanation:

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3 years ago
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yulyashka [42]

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Explanation:

a) The electric force is

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The electric field is related to the potential reference

     V = E d

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    F = e V / d

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        a = 1.6 10⁻¹⁹ / 9.1 10⁻³¹ 28 10³ / 1.4 10⁻²

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Let's calculate the speed

       v = √ (2 3,516 10¹⁷ 1.4 10⁻²)

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2 years ago
A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm
andrew11 [14]

Answer:

2.8 cm

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Distance between two second order minima is given by

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Answer:

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