Answer:
5..No work is being done.
Explanation:
Hello!
Remember that the concept of work is defined as the force required to move a certain body distance, it is calculated as the product of force by distance.
therefore, the work required to raise the box is 150J.
However, the work required to keep the box lifted without moving is zero since although the box has a force due to the weight it does not move.
Answer:
I hope this helps a little bit.
The working equation would be Vf (final velocity) = Vi
(initial velocity) + a (acceleration) t (time). The given data are the initial
velocity (5.0 m/s), acceleration (-2.5 m/s^2, negative since it is said to
decelerate) and the final velocity (0 m/s, since it will put to a stop). The
time would be 2 seconds.
Answer:
The velocity is 
Explanation:
From the question we are told that
The initial speed of the hot water is 
The pressure from the heater 
The height of the hot water before flowing is 
The height of bathtub above the heater is 
The pressure in the pipe is 
The density of water is 
Apply Bernoulli equation

Substituting values

=> ![v_2^2 = \frac{ (450 *10^{3}) + (1000 * 9.8 *0 ) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}](https://tex.z-dn.net/?f=v_2%5E2%20%3D%20%20%5Cfrac%7B%20%28450%20%2A10%5E%7B3%7D%29%20%2B%20%281000%20%2A%209.8%20%2A0%20%29%20%2B%20%280.5%20%2A%201000%20%2A%200.85%5E2%29%20-%5B%20%281000%20%2A%20%2A9.8%2A3.70%29%20%5D%7D%7B0.5%2A1000%7D)
=> ![v_2= \sqrt{ \frac{ (450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}}](https://tex.z-dn.net/?f=v_2%3D%20%5Csqrt%7B%20%5Cfrac%7B%20%28450%20%2A10%5E%7B3%7D%29%20%2B%20%281000%20%2A%209.8%20%2A%200%29%20%2B%20%280.5%20%2A%201000%20%2A%200.85%5E2%29%20-%5B%20%281000%20%2A%20%2A9.8%2A3.70%29%20%5D%7D%7B0.5%2A1000%7D%7D)
=> 