The momentum of the 2.22 kg afterwards is 0.91 kg m/s to the right
Explanation:
We can solve this problem by applying the law of conservation of momentum.
In fact, the total momentum before and after the collision must be conserved. So, we can write:
where:
is the mass of the first block
is the initial velocity of the first block (we take the right as positive direction)
is the final velocity of the first block (to the left)
is the mass of the second block
is the initial velocity of the second block
is the final velocity of the second block
Re-arranging the equation and substituting the values, we find: the final velocity of the second block:
(to the right, since it is positive)
And so, the momentum of the 2.22 kg block afterwards is:
(to the right)
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