Answer:
h = 3.5 m
Explanation:
First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 3.5 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,

Now, we will apply the law of conservation of momentum:

where,
m₁ = mass of colliding ball = 3.6 kg
m₂ = mass of ball on the other end = 3.6 kg
v₁ = vf = final velocity of ball while collision = 8.3 m/s
v₂ = vi = initial velocity of other end ball = ?
Therefore,

Now, we again use the third equation of motion for the upward motion of the ball:

where,
g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)
h = height = ?
vf = final speed = 0 m/s
vi = initial speed = 8.3 m/s
Therefore,

<u>h = 3.5 m</u>
1 milliliter = 1 cubic centimeter (cm^3)
Clarify what you mean by ratios?
Answer:
D
Explanation:
speed = frequency x wavelength
speed of light in vacuum is 3.0 x 10^8
wavelength = 5.32 x10 ^-7
3.0 x 10 ^ 8 = 5.32 x 10^-7 x frequency
frequency = 5.63909 x 10^14
round it off = 5.64 x 10^14 Hz
thus the answer is D
hope this helps please mark it
Answer:
5.95 m
Explanation:
Given that the biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g
For the car to stick to the loop without falling down, at the top of the ride, the centripetal force must be equal to the weight of the car. That is,
(MV^2) / r = mg
V^2/ r = centripetal acceleration which is equal to 2g
2 × 9.8 = 10.8^2 / r
r = 116.64 /19.6
r = 5.95 m