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attashe74 [19]
3 years ago
6

What is happening when two waves with identical crests and troughs meet?

Physics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

When two waves meet in such a way that their crests line up together, then it's called constructive interference. The resulting wave has a higher amplitude. In destructive interference, the crest of one wave meets the trough of another, and the result is a lower total amplitude.

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A large mass collides with a stationary, smaller mass. How will the masses behave if the collision is inelastic?
svlad2 [7]
The larger mass would overpower the lower mass because its not strong enough hope this helped
7 0
4 years ago
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Suppose that a particle's position is described by r(t)=(t+3)i+(t2+2)j. Give an equation (in the form of a formula involving x a
DiKsa [7]

Answer:

The velocity for the particle is (1i+2tj).

Explanation:

Given that,

The particle position is

r(t)=(t+3)i+(t^2+2)j...(I)

In form of x and y

x(t)=t+3....(II)

y(t)=t^2+2...(III)

From equation (II)

t=x-3

Put the value of t in equation (III)

y=(x-3)^2+2

y=x^2+9-6x+2

x^2-6x-y+11=0

We need to calculate the velocity

Velocity is the rate of change of the position of the particle

v(t)=\dfrac{dr}{dt}

\vec{v(t)}=1i+2t j

Hence, The velocity for the particle is (1i+2tj).

6 0
3 years ago
About 3% of the water on Earth is freshwater. Only about 40% of that freshwater is available for human use. Why is so much fresh
Pie
A) it is frozen i think
7 0
3 years ago
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A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position
kaheart [24]

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

4 0
3 years ago
A motorist enters a freeway at 45 km/h and accelerates uniformly to 99 km/h. From the odometer in the car, the motorist knows th
Marat540 [252]

Answer:

a)  19440 km/h²

b) 10 sec

Explanation:

v₀ = initial velocity of the car = 45 km/h

v = final velocity achieved by the car = 99 km/h

d = distance traveled by the car while accelerating = 0.2 km

a = acceleration of the car

Using the kinematics equation

v² = v₀² + 2 a d

99² = 45² + 2 a (0.2)

a = 19440 km/h²

b)

t = time required to reach the final velocity

Using the kinematics equation

v = v₀ + a t

99 = 45 + (19440) t

t = 0.00278 h

t = 0.00278 x 3600 sec

t = 10 sec

5 0
3 years ago
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