<span>The preparation of 40 liters of 0.02 m phosphate buffer, ph 6.9, may be carried out by adding 132g of solid trisodium phosphate to 1290ml of hydrochloric acid (HCl concentration 1 mol/L), then making up to a final liquid volume of 40 liters by adding water.
Method: Weigh out 132 grams of Na3PO4 (s), and add it to 1290 ml 1M HCl (l). Mix, then add water, to a final volume of 40 liters.</span>
What are the statements? A chemical property is a characteristic of a particular substance that can be observed in a chemical reaction
Answer:
The new volume will be
0.7 L
Explanation:
This is an illustration of Charles' law, some of the time called the temperature-volume law. It expresses that the volume of a gas is straightforwardly corresponding to the Kelvin temperature, while pressing factor and sum are held steady. The condition is V 1 T 1 = V 2 T 2 , where V is volume and T is temperature in Kelvins. Known V 1 = 0.5 L T 1 = 20 ∘ C + 273.15 = 293 K T 2 = 150 ∘ C + 273.15 = 423 K Obscure V 2 Arrangement Revise the condition to confine V 2 . Substitute the known qualities into the condition and address. V 2 = V 1 T 2 T 1 V 2 = ( 0.5 L × 423 K ) 293 K = 0.7 L adjusted to one huge figure
Answer:
The correct set of measurement is D