1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Butoxors [25]
3 years ago
6

The number of valence electrons in an atom with an electron configuration is 1s2 2s2 2p6 3s2 3p4

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

6 valence electrons

Explanation:

The atom you have given is a sulfur atom. It has 6 valence electrons.

You might be interested in
Explain how the use of CNG in automobile has reduced pollution in our cities.​
sertanlavr [38]

Answer:

I think by charging

Explanation:

With charger

3 0
3 years ago
Which is a common way for a scientific calculator to show the number below? <br> 8.1 102
Elodia [21]
Answer: 8.1e+2 or 8.1E+2 (in the scientific notation mode), based on that the number given is 8.1 × 10².

Explanation


Scientific calculators use the letter e or E to show the numbers in scientific notation mode.

These are some examples of numbers that require scientific notation and how they are shown.

Number                 Scientific calculator display

6.022 × 10²³           6.022 e+23
5 × 10 -12              5 E -12

So, understanding that your question is about number 8.1 × 10², the scientific calculator could show  8e+2.

Nevertheless, since 8 .1 × 10² is 810, not a long number, if the display is not in scientific notation mode, it could just display just 810,

7 0
3 years ago
Aluminum chloride is added to cesium does a single replacement reaction occur, and if so what is the correct chemical equation f
krek1111 [17]
The answer is C

I hope that helped
5 0
3 years ago
Read 2 more answers
Limiting Reactant Worksheet
faltersainse [42]

Answer:

a) 1.61 mol

b) Al is limiting reactant

c) HBr is in excess

Explanation:

Given data:

Moles of Al = 3.22 mol

Moles of HBr = 4.96 mol

Moles of H₂ formed = ?

What is limiting reactant =

What is excess reactant = ?

Solution:

Chemical equation:

2Al  + 2HBr  → 2AlBr + H₂

Now we will compare the moles:

                Al              :               H₂

                  2              :               1

                 3.22         :            1/2×3.22 = 1.61 mol

                HBr            :              H₂

                 2                :               1

                4.96            :          1/2×4.96 = 2.48 mol      

The number of moles of H₂ produced by Al are less it will be limiting reactant while HBr is present in excess.

Moles of H₂ :

Number of moles of H₂ = 1.61 mol

6 0
3 years ago
Match the term with the definition.
alina1380 [7]
What term and what definition..
5 0
3 years ago
Read 2 more answers
Other questions:
  • The maximum amount of product that can be produced from a given amount of reactant is known as ______________________.
    10·2 answers
  • Sentence for death rate
    10·1 answer
  • Which of the following mass units is the largest? a) 1 cg b) 1 dg c) 1 mg d) 1 ng
    15·2 answers
  • If the crucible is contaminated with the volatile impurities. While heating, the impurity is then burned off and removed. Descri
    7·1 answer
  • Draw the Lewis Structure for H2O.
    15·1 answer
  • A balloon holds a certain volume of air. In what three ways can the volume of the balloon be increased?
    13·1 answer
  • The reaction converting glycerol to glycerol-3-phosphate is energetically unfavorable by 9.2 kJ. The reaction of ATP with water
    12·1 answer
  • Balance the redox reaction equation (occurring in acidic solution) and choose the correct coefficients for each reactant and pro
    13·1 answer
  •  how are subscripts determine the formula of ionic and covalent compounds ?
    14·1 answer
  • A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!