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Vanyuwa [196]
2 years ago
14

Which phase or phases of matter take(s) the shape of its container?

Chemistry
1 answer:
Vladimir79 [104]2 years ago
8 0
I'm pretty sure it's C. 

A gas can be compressed, but I'm not sure that it actually takes the shape. 
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The carbon atoms in graphite and the carbon atoms in diamond have different
kicyunya [14]

Answer:

<u>structural arrangements</u>

_______________________________________

<h2>properties of daimond: </h2><h3>appearance: transparent</h3><h3>hardness: very hard</h3><h3>thermal conductivity :very poor</h3><h3>electric conductivity: poor</h3><h3>density:</h3>

3510 {kgm}^{3}

<h3>uses: jewellery and drilling</h3>

_______________________________________

<h2>properties of graphite:</h2>

<h3>appearance: black shiny</h3><h3>hardness: soft ,slippery to touch</h3><h3>thermal conductivity : moderate</h3><h3>electric conductivity: good</h3><h3>density:</h3>

2250 {kgm}^{3}

<h3>uses:dry cell, electric arc, pencil lead, lubricant</h3>

_______________________________________

<h2>How Diamond and Graphite are chemically identical?</h2>
  • On heating diamond or graphite in the air, they burn completely to form carbon dioxide.
  • - Equal quantities of diamond and graphite when burned, produce exactly the same amount of carbon dioxide.

_______________________________________

<h2>Why the physical properties of diamond and graphite are so different?</h2>

Due to the difference in the arrangement of carbon atoms in diamond and graphite

_______________________________________

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>

7 0
2 years ago
Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.
Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liter}.

<h3>Molarity in this case</h3>

In this case, you have:

  • number of moles= 0.2 moles
  • volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

molarity=\frac{0.2 mole}{0.1 L}

Solving:

<u><em>molarity= 2 </em></u>\frac{moles}{liter}

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

8 0
2 years ago
What is the most effective way to differentiate between potassium feldspar and plagioclase feldspar?
Tresset [83]
<span>plagioclase feldspars have striations and potassium feldspars don't have striations</span>
3 0
3 years ago
Antibiotics do not reduce the number of helpful and harmful bacteria in the microbiome.
stira [4]

Answer:

false; the purpose of antibiotics is to kill bacteria

Explanation:

7 0
3 years ago
Read 2 more answers
A fat is composed of long chains of carbon and hydrogen atoms. In a reaction with a strong base, a fat forms a soap and glycerol
Nonamiya [84]

Answer:

Empirical formula is C₉H₁₅O

Molecular formula = C₈₁H₁₃₅O ₉

Explanation:

Percentage of carbon = 77.60%

Percentage of oxygen = 11.45%

Percentage of hydrogen = 10.95%

Molecular weight = 1253 g/mol

Molecular formula = ?

Empirical formula = ?

Solution:

Number of gram atoms of C = 77.60 g /12g/mol =6.5

Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72

Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9

Atomic ratio:

C               :            H                 :    O

6.5/0.72   :       10.9/0.72         :   0.72/0.72

     9          :            15              :         1

C : H : O = 9 : 15 : 1

Empirical formula is C₉H₁₅O

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 1253 / 139

n = 9

Molecular formula = n (empirical formula)

Molecular formula = 9 (C₉H₁₅O )

Molecular formula = C₈₁H₁₃₅O ₉

4 0
3 years ago
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