Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters
Kelly walks 5km.
1 km = 1000m.
5x1000 = 5000meters
1.5h = 90minutes
90miX60 = 5400s
10m/54s
And so on
He treated then with care he would get more help or what he needed
A) position time graph for both is shown
here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed
At one point they intersects which is the point where they both will meet
B) Let the two will meet after time "t"
now we can say that
if they both will meet after time "t"
then the total distance moved by you and other person will be same as the distance between you and home
so it is given as



so they will meet after t = 6 min
so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect