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DiKsa [7]
3 years ago
6

What physical quantity is a measure of the amount of inertia an object has?

Physics
1 answer:
Jlenok [28]3 years ago
5 0
Most common quantity of inertia is mass
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What is the logical oreder for these words : verse, interlude,verse,refrain, introduction,refrain,coda,refrain,verse
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Sorry to say but I know that t(e introduction is first and the coda is last


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4 years ago
Which of the following compounds does not contain molecules? A. H2 B. NaCl C. CO2 D. H2O
klio [65]
B. NaCl

All of the other answers contain a 2 or a number in general. Metals do not form covalent bonds. Alkali-halide salts are Ionic compounds. Ionic compounds form from bonding a metal and a non metal. Covalent bonds are formed by bonding non metals.
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You describe a friend’s position by including distance, direction, and what other term?
garik1379 [7]

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Explanation:

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3 years ago
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A truck traveling at a constant speed of 28 m/s passes a more slowly moving car. The instant the truck passes the car, the car b
choli [55]

Answer:

the velocity of car when it passes the truck is u = 16.33 m/s

Explanation:

given,

constant speed of truck  = 28 m/s

acceleration of car = 1.2 m/s²

passes the truck in 545 m

speed of the car when it just pass the truck = ?

time taken by the truck to travel 545 m

              time =\dfrac{distance}{speed}

              time =\dfrac{545}{28}

              time =19.46 s

velocity of the car when it crosses the truck

S = ut + \dfrac{1}{2}at^2

545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2

u = 16.33 m/s

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5 0
4 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that
Natasha2012 [34]

Answer:

g = 11.2 m/s²

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First, we will calculate the time period of the pendulum:

T = \frac{t}{n}

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

T = \frac{135\ s}{98}

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

T = 2\pi \sqrt{\frac{l}{g}}

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}

<u>g = 11.2 m/s²</u>

3 0
3 years ago
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