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BartSMP [9]
3 years ago
12

Which part of the fuel cell does A represent?

Chemistry
2 answers:
Bad White [126]3 years ago
8 0

I think the anwer is electrolyte :)... i had it on a test a couple days ago.

kirill115 [55]3 years ago
4 0

Answer:

The answer is D electrolyte

Explanation:

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Which of the following are examples of elements?<br> a. CO<br> b. Li<br> c. KBr<br> d. Ca
bogdanovich [222]

\huge\boxed{\textsf{Li and Ca}}

An element is a substance that can't be broken down further. Lithium (Li) and calcium (Ca) are examples of elements.

Carbon monoxide (CO) and potassium bromide (KBr) are examples of compounds, which are made up of more than one element put together.

6 0
1 year ago
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Which property describes a mixture? It cannot be separated by physical methods. It has a single chemical composition. It cannot
natima [27]

Answer:

it cannot be separated by physical methods

Explanation:

7 0
3 years ago
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Tell me a hypothesis for the corrosion experiment for iron nails?
Nastasia [14]
The more acidic the substance is, the more the iron nails will corrode (this obviously depends on what your experiment is but hope this helped in some way)
5 0
3 years ago
Calculate the boiling temperature of a 0.50 M solution of sucrose. Assume that the concentration is 0.50 m.
Ronch [10]
There is one missing point in the question.

The formula to find an increase in boiling Temperature is :

ΔT = kb x M

ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity

You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.


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5 0
3 years ago
Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

3 0
2 years ago
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