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Dennis_Churaev [7]
3 years ago
10

How much 0.85 M HCl solution can be made by diluting 250 mL of 10 M HCl?

Chemistry
2 answers:
liubo4ka [24]3 years ago
8 0
The amount of 0.85M HCl solution that can  be made  by diluting 250 ml of 10M HCl is calculated using

M1V1=M2V2  formula

M1=0.85M
V1=?
M2= 10M
V2= 250 ml

by making the V1 the subject of the formula
V1 = M2V2/M1

V1 = (10 Mx250 ml)/ 0.85 M =2941.2 ml
7nadin3 [17]3 years ago
7 0

<span>Answer is:  2940 mL of the HCL solution.</span>

c₁(HCl) = 10.0 M.

V₂(AgNO₃<span>) = ?.
c</span>₂(AgNO₃<span>) = 0.85 M.
V</span>₁(AgNO₃<span>) = 250 mL </span>÷ 1000 mL/L = 0.25 L.

<span> c</span>₁<span> - original concentration of the solution, before it gets diluted.
c</span>₂<span> - final concentration of the solution, after dilution.
V</span>₁<span> - volume to be diluted.
V</span>₂<span> - final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
V</span>₂(HCl) = c₁ · V₁ ÷ c₂.

<span> V</span>₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.

<span> V</span>₂(HCl) = 2.94 L · 1000 mL = 2940 mL.

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