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Ulleksa [173]
3 years ago
13

The volume of a sphere is (4/3πr3 and the density of copper is 8.96g/cm3. part a what is the radius (in cm of a pure copper sphe

re that contains 1.59×1024 copper atoms?
Chemistry
1 answer:
ira [324]3 years ago
8 0
<span> <span> </span></span>Volume = 4/3 * PI * r^3

1.59 x 10^24 copper atoms = 2.64 moles of copper
Atomic Mass of copper = 63.55
2.64 * 63.55 = 167.77 grams of copper
Volume of Copper = Mass / Density
Volume of Copper = 167.77 grams / 8.96
Volume of Copper = <span> <span> 18.72</span></span> cubic centimeters

r^3 = Volume / (4/3 * PI)
r^3 = 18.72 / 4.188
r^3 = <span> <span> <span> 4.47
radius = </span></span></span><span><span><span>1.647</span> centimeters

</span></span>
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2 years ago
The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
svp [43]
Q: A
according to this formula, we can get the mole fraction of water (n):
P(solu) = n Pv(water)
when we have Pv(solu) = 22.8 and Pv(water) = 23.8 so by substitution:
22.8 = n * 23.8
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n = moles of water / ( moles of water + moles of glucose)
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Q: B
here we also need to get n (mole fraction of water )by using this formula:
Pv(solu) = n Pv(water)
when we have Pv(solu)=132 & Pv(water)=150 so, by substition:
132= n * 150
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- total moles in solution = moles of water / moles fraction of water 
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∴ moles of the solution = total moles in solu - moles of water 
                                       = 5.34 - 4.7 = 0.64 moles solute
∴ the molar mass of the solute = mass weight of solute / no.of moles of solute
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Pv(solu) = n P°v
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