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Ulleksa [173]
3 years ago
13

The volume of a sphere is (4/3πr3 and the density of copper is 8.96g/cm3. part a what is the radius (in cm of a pure copper sphe

re that contains 1.59×1024 copper atoms?
Chemistry
1 answer:
ira [324]3 years ago
8 0
<span> <span> </span></span>Volume = 4/3 * PI * r^3

1.59 x 10^24 copper atoms = 2.64 moles of copper
Atomic Mass of copper = 63.55
2.64 * 63.55 = 167.77 grams of copper
Volume of Copper = Mass / Density
Volume of Copper = 167.77 grams / 8.96
Volume of Copper = <span> <span> 18.72</span></span> cubic centimeters

r^3 = Volume / (4/3 * PI)
r^3 = 18.72 / 4.188
r^3 = <span> <span> <span> 4.47
radius = </span></span></span><span><span><span>1.647</span> centimeters

</span></span>
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Draw the product that is formed when the compound shown below is treated with an excess of hydrogen gas and a platinum catalyst.
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<span>When the hexene is treated with an excess of hydrogen gas and a platinum catalyst, the product formed is hexane.

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5 0
3 years ago
The table shows the mass and boiling point of some substances.
Westkost [7]

N is the unit of force. It stands for Newton.


M is the unit of length.


It stands for Meter.


It is the basic difference between the two units N and M.


Answer: N - Newton; M - Meter


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5 0
3 years ago
Please please please help me ill give brainliest
Mnenie [13.5K]

Answer: the answer is A.

8 0
3 years ago
C. Use Hess's law and the following equations to calculate ΔH for the reaction 4NH3 (g) + 5O2 (g) 4NO(g) + 6H2 O(g). Show your w
Monica [59]

Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

<h3>Hess's Law</h3>

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

<h3>ΔH in this case</h3>

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃   ΔH = –183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O     ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂  ΔH = 183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O     ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

Learn more about Hess's law:

brainly.com/question/5976752

brainly.com/question/13707449

brainly.com/question/13707449

brainly.com/question/6263007

brainly.com/question/14641878

brainly.com/question/2912965

#SPJ1

7 0
2 years ago
For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values
In-s [12.5K]

Answer : The temperature in kelvins is, T>1108.695K

Explanation : Given,

\Delta H = 178.5 KJ/mole = 178500 J/mole

\Delta S = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

\Delta G=\Delta H-T\Delta S

As per question the reaction is spontaneous that means the value of \Delta G is negative or we can say that the value of \Delta G is less than zero.

\Delta

The above expression will be:

0>\Delta H-T\Delta S

T\Delta S>\Delta H

T>\frac{\Delta H}{\Delta S}

Now put all the given values in this expression, we get :

T>\frac{178500J/mole}{161.0J/mole.K}

T>1108.695K

Therefore, the temperature in kelvins is, T>1108.695K

7 0
3 years ago
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