I believe the correct answer from the choices listed above is the third option. It would be chromium (Cr) that is a transition metal. The 38 elements in groups 3 through 12 of the periodic table are called "transition metals<span>". Hope this answers the question. Have a nice day.</span>
Answer:
If you are asking why the atomic mass on the periodic table only goes to the hundredth's place, it is because of significant figures. No number is exact, like it can be 63.5500001, and it will go to a certain point before it cease to matter in experiments.
Answer:In general, yes. Usually, you talk about the reflectivity/emissivity of a surface rather than an object. Typically, you’d find a coefficient of emissivity (since emission and absorption are normally equivalent processes in reverse) for the surface, ideally as a function of wavelength and incident angle. Then you apply that coefficient to all light striking the object.
Assuming an opaque object, reflectivity (call it R) has a simple relationship to emissivity (call it E): R=1-E. You can measure reflectivity with a calibrated light source and light sensor, for example. It’s a little trickier, but you can also measure emissivity through techniques like calorimetry, where you measure how much something heats up to figure out how much energy was deposited; again, a calibrated light source can be used to direct a certain amount of power onto a test object, and the heating tells you how much power is retained. You can also get emissivity by heating an object and observing how much power it emits by blackbody radiation.
To be really thorough, you might also want to measure transmissivity, in case the object isn’t opaque. If we call transmissivity “T,” we really have to write R+E+T=1 (which just says that all the incident light has to either reflect, absorb, or pass through).
If the object is something celestial, of course, it’s harder to use these methods, but not impossible. For example, we can measure how much light the full moon reflects, and knowing how much light hits it from the sun, we can find the reflectivity; in principle, we could use our knowledge of how much the surface of the moon is heated by the sun to find the emissivity, as well. For that kind of calculation, it’s important to know how large and how distant an object is, to figure out how much of its reflected light makes it back to you.
Explanation:
Answer:
Trimethylacetaldehyde
Explanation:
For the <u>unknow compound</u> we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does <u>not have nitrogen</u> and we can have several posibilities:
A) 
B) 
C) 
D) 
If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an <u>oxo group</u> (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, <u>Ketones and aldehydes</u>.
We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very<u> symmetric compound</u>.
By trial an error the find the compound <u>Trimethylacetaldehyde</u> (Figure 1).
