The term amphoteric describes a substance that can act as both an acid and a base.
Answer:
Option B. 6 atoms of carbon
Explanation:
In <u><em>any chemical reaction</em></u>, atoms from reactant side and product side must be the same.
This is photosynthesis reaction:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of 
Formula used :

where,
are the initial molarity and volume of
.
are the final molarity and volume of
.
We are given:

Putting values in above equation, we get:

Now we have to calculate the total volume of solution.
Total volume of solution = Volume of
+ Volume of 
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.

Now we have to calculate the pH of the solution.
At equivalence point,
![pOH=\frac{1}{2}[pK_w+pK_b+\log C]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5BpK_w%2BpK_b%2B%5Clog%20C%5D)
![pOH=\frac{1}{2}[14+4.87+\log (0.0437)]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5B14%2B4.87%2B%5Clog%20%280.0437%29%5D)


Thus, the pH of the solution is, 5.24
Answer : The number of molecules present in nitrogen gas are,
Explanation :
First we have to calculate the moles of nitrogen gas by using ideal gas equation.
where,
P = Pressure of
gas =
(1 atm = 760 mmHg)
V = Volume of
gas = 985 mL = 0.982 L (1 L = 1000 mL)
n = number of moles
= ?
R = Gas constant =
T = Temperature of
gas =
Now put all the given values in above equation, we get:

Now we have to calculate the number of molecules present in nitrogen gas.
As we know that 1 mole of substance contains
number of molecules.
As, 1 mole of
gas contains
number of molecules
So,
mole of
gas contains
number of molecules
Therefore, the number of molecules present in nitrogen gas are,
Answer:
1.78 × 10⁹ μg
Explanation:
We have to convert 1.78 kg to μg.
Step 1: Convert 1.78 kilograms to grams
We will use the conversion factor 1 kg = 10³ g.
1.78 kg × 10³ g/1 kg = 1.78 × 10³ g
Step 2: Convert 1.78 × 10³ grams to micrograms
We will use the conversion factor 1 g = 10⁶ μg.
1.78 × 10³ g × 10⁶ μg/1 g = 1.78 × 10⁹ μg