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omeli [17]
3 years ago
14

What kind of object has an indefinite shape and indefinite volume? IH

Chemistry
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

Gas neither has definite volume nor definite shape.

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NEED HELP ASAP
Fantom [35]

Answer:

D. potential

Explanation:

D. potential

5 0
2 years ago
Read 2 more answers
A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
Tasya [4]

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0
3 years ago
Read 2 more answers
A compound with the empirical formula ch2 has a molar mass of 70 g/mol. what is the molecular formula for this compound?
Rainbow [258]

The empirical formula, <span>C<span>H2</span></span>, has a relative molecular mass of

<span>1×<span>(12.01)</span>+2×<span>(1.01)</span>=14.04</span>

This means that the empirical formula must be multiplied by a factor to bring up its molecular weight to 70. This factor can be calculated as the ratio of the relative masses of the molecular and empirical formulas

<span><span>7014.04</span>=4.98≈5</span>

Remember that subscripts in molecular formulas must be in whole numbers, hence the rounding-off. Finally, the molecular formula is

<span><span>C<span>1×5</span></span><span>H<span>2×5</span></span>=<span>C5</span><span>H<span>10</span></span></span>

5 0
3 years ago
Read 2 more answers
1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen
Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
3 years ago
Dibujo de la estructura de lewis con las siguientes iones o moléculas Pbi4 y AgNO3NO​
11111nata11111 [884]

i dont have a clue i dont know h       ave a lcue

7 0
2 years ago
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