Determine the translation that maps point C(7,5) to point C'(5,5).
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Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is
Slope of lines NY is
Product of slopes of two perpendicular lines is -1. So,
The perpendicular bisector of NY passes through (-4,1) with slope . So, the equation of perpendicular bisector of NY is
Add 1 on both sides.
Therefore, the equation of perpendicular bisector of NY is .