Answer:
u= 200 m/s
Explanation:
Given that
Mass of bullet ,m= 50 gm
Assume that mass of block ,M= 1.2 kg
Lets take speed of the bullet before collision = u m/s
The speed of the system after collision ,v= 8 m/s
There is no any external force ,that is why linear momentum of the system will be conserve.
Linear momentum ,P = mass x velocity
m u = (M+m)v
0.05 x u = (1.2 + 0.05 ) x 8
u= 200 m/s
Therefore the speed of the bullet just before the collision is 200 m/s.
Acceleration is the rate of change of velocity per unit of time.
Explanation:
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Respuesta:
4.9 × 10³ J
Explicación:
Paso 1: Información provista
- Masa del coyote (m): 30 kg
- Velocidad del coyote (v): 65 km/h
Paso 2: Convertir la velocidad del coyote de km/h a m/s
Vamos a usar los siguientes factores de conversion:
65 km/h × (1000 m/1 km) × (1 h/3600 s) = 18 m/s
Paso 3: Calcular la energía cinética del coyote (K)
Usarémos la siguiente fórmula.
K = 1/2 × m × v²
K = 1/2 × 30 kg × (18 m/s)² = 4.9 × 10³ J
