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Natasha2012 [34]
2 years ago
9

IF SOME ONE SENDS U A LINK DO NOT PUSH ON IT CUZ THEY WILL HACK UR STUFF .................. BE CAREFUL PLZ

Physics
1 answer:
Karolina [17]2 years ago
7 0

i know that please spread the word around so everyone can know!

it will help us a very much lot,

thanks.

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HEY CAN YALL PLS HELP ME IN DIS!!!!!!!!!!!!!
Serga [27]

Answer:

Hey!!

Your answer is: 0.72

Explanation:

if 760=1  then...

550=x

=550÷760= 0.72 in two s.f

6 0
3 years ago
HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in
In-s [12.5K]
Talk about the jobs that pipeline construction provides to citizens and wether or not it’s effects are ultimately eco-friendly
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3 years ago
A gymnast dismounts off the uneven bars in a tuck position with a radius of 0.3m (assume she is a solid sphere) and an angular v
kifflom [539]

Here we will say that there is no external torque on the system so we will have

L_i = L_f

here we know that

L_i = I_1\omega_1

where we know that

I_1 = \frac{2}{5}mr^2

Also we know that

I_2 = \frac{1}{12}mL^2

initial angular speed will be

\omega_1 = 2\pi(2rev/s) = 4\pi rad/s

now from above equation

\frac{2}{5}mr^2 (4\pi) = \frac{1}{12}mL^2 \omega

0.4(0.3)^2(4\pi) = \frac{1}{12}(1.5)^2\omega

0.452 = 0.1875 \omega

now we have

\omega = 2.41 rad/s

so final speed will be 2.41 rad/s

6 0
2 years ago
Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
Scilla [17]

Answer:

d= 5.62 m

Explanation:

In order to have destructive interference, the path difference from the sources to the listener must be an odd multiple of half wavelengths, as follows:

d = (2n+1) * λ/2

In orfer to know which is the wavelength, we can use the relationship between propagation speed (in this case speed of sound), frequency and wavelength:

v= λ*f  ⇒ λ = v/f = 344 m/s / 688 1/sec = 0.5 m

So, the path difference must be, at least, λ/2:

d = b-a = λ/2, where b is the distance to the speaker B, and a, the distance to the speaker A.

Applying Pithagorean Theorem, as the perpendicular distance d (which is our unknown) is the same for the triangles defined by the horizontal distance to the listener, and the straight line from the new position to the sources, we can write:

d² = a²- (3.0)²

d² = b²- (3.5)²

As the left sides are equal, so do right sides:

a² - (3.0)² = b² - (3.5)²

⇒ b² - a² = (3.5)² - (3.0)² = 3.25

We can replace (b²- a²) as follows:

b² - a² = (b+a)(b-a) = 3.25 (2)

We know that b-a = λ/2 = 0.25

Replacing in (2), we have:

b+a = 3.25 / 0.25 = 13 m

b-a = 0.25 m

Adding both sides:

2*b = 13.25 m  ⇒ b= 13.25 /2 = 6.63 m

⇒ d² = (6.63)² - (3.5)² = 31.6 m²

⇒ d=√31.6 m² = 5.62 m

3 0
2 years ago
Why are dispersion forces weaker than dipole
vazorg [7]
One is temporary one is permanent
5 0
3 years ago
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