Answer: conservative model
Explanation: DNA isolated after one generation produced a single band which was a higher and intermediate in density between the heavy and light Nitrogen isotopic DNA used, showing that the first generation was a hybrid DNA. This observation fit with the dispersive and semi-conservative models only. And so at this generation, the conservative model was discarded.
Gram-positive bacteria are bacteria that have thick cell walls which yield positive results in the Gram staining test. Lipoteichoic acid is a major component of the cell wall of gram-positive bacteria.
- All bacteria indicated in the question can be classified by the Gram staining test:
- Actinomycetes are Gram-positive bacteria
- The genus <em>Arthrobacter </em>includes Gram-positive bacteria
- <em>Escherichia coli </em>(<em>E. coli</em>) is a Gram-negative bacterium
- <em>Staphylococcus spp.</em> are Gram-positive bacteria
- <em>Bacillus spp</em> are Gram-positive bacteria
- <em>Mycobacterium spp.</em> are Gram-positive bacteria
- Prokaryotes can be divided into two domains: Bacteria and Archaea.
- Gram staining is a method used to classify bacteria, but this method IS NOT USED to stain Archaea.
- In consequence, I would not use the Gram test to stain Archaebacteria because Archaebacteria aren't bacteria (Option A is correct).
- Archaebacteria belong to the Archaea domain.
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2nd choice is the correct one
Is this like on a test or like homeowork?
<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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