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alukav5142 [94]
3 years ago
5

The dean of a college is interested in the proportion of graduates from his college who have a job offer on graduation day. He i

s particularly interested in seeing if there is a difference in this proportion for accounting and economics majors.
In a random sample of 100 of each type of major at graduation, he found that 65 accounting majors and 52 economics majors had job offers. If the accounting majors are designated as "Group 1" and the economics majors are designated as "Group 2," perform the appropriate hypothesis test using a level of significance of 0.05.
(A) The hypotheses the dean should use are:

a) H0 : π1 - π2 ≥ 0 versus H1 : π1 - π2 < 0.
b) H0 : π1 - π2 ≤ 0 versus H1 : π1 - π2 > 0.
c) H0 : π1 - π2 ≠ 0 versus H1 : π1 - π2 = 0.
d) H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.

(B) Referring to the scenario above, the null hypothesis will be rejected if the test statistic is ________.
(C) Referring to the scenario above, the value of the test statistic is ________.
(D) Referring to the scenario above, the p-value of the test is ________.
Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

A. D

B. χ2 > 3.841

C. χ2 = 3.4806

D. 0.0621

Step-by-step explanation:

Question A: The hypotheses the dean should use are:

a) H0 : π1 - π2 ≥ 0 versus H1 : π1 - π2 < 0.

b) H0 : π1 - π2 ≤ 0 versus H1 : π1 - π2 > 0.

c) H0 : π1 - π2 ≠ 0 versus H1 : π1 - π2 = 0.

d) H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.

Answer: (d)

H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.

(B). Referring to the scenario above, the null hypothesis will be rejected if the test statistic is ________.

Answer: χ2 > 3.841

(C). Referring to the scenario above, the value of the test statistic is ________.

Answer: χ2 = 3.4806 (using the formula)

(D). Referring to the scenario above, the p-value of the test is ________.

Answer: 0.0621 (the answer could be looked up, in table)

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Question 4 Are there any outliers in the data sets? If there are outliers, do they lie at the lower end or at the higher end of
Komok [63]

Answer:

The center of Walden’s data, 3, is less than the center of Drake’s data set, 6.

Step-by-step explanation:

3 0
3 years ago
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Between what two integers does 160 lie
Annette [7]
An integer is a whole number, not a fraction or decimal. Integers can be positive or negative. 180, 4, 17, -56 are all integers. 4.5, 38 1/2, 88.7 are not integers because they are not whole numbers.

ANSWER: 160 lies between 159 and 161.

Hope this helps! :)
8 0
3 years ago
Find the sum. 2/5(d-10)-2/3(d+6)
alukav5142 [94]

Answer:

-4d

Step-by-step explanation:

L.c.m=15

15×2/5(d-10)-2/3×15(d+6)

3×2(d-10)-2×5(d+6)

6(d-10)-10(d+6)

6d-60-10d-60

6d-10d-60-60

-4d-0

-4d

5 0
2 years ago
Need help simple explanation if possible
photoshop1234 [79]

Answer:

m < A = 60º

m < B = 30º

Step-by-step explanation:

The given sides on this triangle are: 6, 6\sqrt{3}, and 12

Any triangle with the angles of 30º - 60º - 90º always has side lengths in this proportion:

x, x\sqrt{3}, 2x

We can line this up with the given sides. If x is 6, then 2x would be 12.

x : x\sqrt{3} : 2x = 6 : 6\sqrt{3} : 12

Angle B is across from 6, the shortest side. That also means that it corresponds to x, or the smallest angle in the proportion, 30º.

m < B = 30º

Solving for < A:

Method 1) Sum of Angles in a Triangle

Since we already know that one angle is right and therefore 90º and m < B is 30º, we can subtract these from the total sum of angle measures in a triangle to get the last angle, < A.

180º - 90º - 30º = 60º

m < A = 60º

Method 2) Using the second part of the proportion

Since m < A is across from the second largest side, we know that it is equal to x\sqrt{3} (6\sqrt{3} in this question) or 60º in the angle proportion.

This means that m < A = 60º

Let me know if you have any questions!

4 0
2 years ago
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The manufacturer of the ColorSmart-5000 television set claims 95 percent of its sets last at least five years without needing a
patriot [66]

Answer:

Step-by-step explanation:

Hello!

Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"

X~Bi (n;ρ)

ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95

n= 390

x= 303

sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78

Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.

You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:

^ρ±Z_{1-\alpha /2}* √[(^ρ(1-^ρ))/n]

Z_{1-\alpha /2} = Z_{0.995} = 2.58

0.78±2.58* √[(0.78(1-0.78))/390]

0.0541

[0.726;0.834]

With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.

I hope it helps!

7 0
3 years ago
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