Answer:
The role that chlorine atoms have in increasing the depeltion rate ozone is that Cl acts as a catalyst.
Explanation:
- From the two steps of the reaction:
- O₃ + Cl· → ClO· + O₂
- ClO· + O → Cl· + O₂
- The overall reaction is: O₃ + O → 2O₂
- It is clear that ClO· is an intermediate that has been produced within the first step and has been consumed in the second step.
- Also, Cl· is considered as a catalyst in this reaction that it has been consumed in the first step and has been produced in the second step, which means that it does not get up in the reaction, that is the main characteristic of the catalyst.
- The catalyst usually increases the rate of the reaction by lowering its energy of activation (The minimum energy that is required to initiate the reaction) by proceeding the reaction in an alternative pathway <em>(changing the reaction mechanism)</em>.
- Hence, the role affecting the reaction rate that chlorine atoms have in increasing the depletion rate of ozone that it acts as a catalyst and does not get used up in the reaction.
Answer:
Just say I wonder why teachers give homework :/
Explanation:
Answer:
B. Poor conductor.
Explanation:
It cannot be A, as only 1 metal is not solid at room temp.
It cannot be C, as most metals are ductile.
It cannot be D, as most metals are malleable.
This leaves B, which is not true about metals, as a lot are very good conductors.
It represents a conservation in mass because the actual mass of water isn’t changing. The relationship between the molecules and the density of the water is. There is still the same amount of mass.
The electron geometry is tetrahedral and the molecular geometry is tetrahedral. If a molecule of CH3OCH3 is to be drawn, the two carbons would have four single bonds and the middle O would have two single bonds and the two lone pairs. Molecular geometry does not consider the lone pairs as bonds like in electron domain geometry. However, since the carbons do not contain any lone pairs, its electrons domain and molecular geometry will be the same. Therefore; Both carbons are tetrahedral for electron domain geometry and molecular geometries. The O is tetrahedral for the electron domain geometry and bent for molecular geometry.
