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astraxan [27]
3 years ago
12

You will mostly find me in solid form at room temperature.

Chemistry
1 answer:
AlexFokin [52]3 years ago
5 0
Nonmetal is the correct answer
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Please answer fast if can, will give Brainiest
Vilka [71]

From the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains (option D).

<h3>What is the absorption spectra?</h3>

The absorption spectra shows us the energy that is taken in by a gas. We know that when a gas is heated, it absorbs energy which shows up in its absorption spectra.

Thus, from the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains.

Learn more about absorption spectra:brainly.com/question/4239971

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7 0
2 years ago
Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model
AfilCa [17]

Answer:

B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

AND

C. The modern model explains all available data about atoms; Bohr’s model does not.

Explanation:

The answers are right on Edge. :)

6 0
3 years ago
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Musya8 [376]
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3 0
4 years ago
n the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of
Xelga [282]
0.075 L * 1.0 M = 0.075 mol HCl
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8 0
4 years ago
600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c
Ludmilka [50]

Answer:

k=1.20x10^{-3} s^{-1}

Explanation:

For a first order reaction the rate law is:

v=\frac{-d[A]}{[A]}=k[A]

Integranting both sides of the equation we get:

\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

ln\frac{[A]}{[A]_{0} } =-kt

[A]=[A]_{0}e^{-kt}

ln[A]=ln[A]_{0} -kt

k=\frac{ln[A]_{0}-ln[A]}{t}

therefore k is

k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}

8 0
4 years ago
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