Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms. The bottle
slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground. The vertical height from where Jeff dropped the bottle is ___ meters. Ignore friction, and use K E = 1/2 MV², PE = m × g × h, and g = 9.8 m/s2.
2 answers:
You might be interested in
Answer:
Time will be 5 sec
And maximum height will be 1200 feet
Explanation:
We have given that initial velocity of the object u = 160 ft/sec'
Function of height
Take derivative of the distance
We know that first derivative of distance is velocity
So
At maximum height we know that velocity is zero
So
t = 5 sec
So it will take 5 sec to reach maximum height
Now maximum height will occur at t = 5 sec
So maximum height =