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matrenka [14]
2 years ago
13

The train departed 100 meters in 10 seconds How far has the train gone in the last 2 seconds

Physics
1 answer:
zzz [600]2 years ago
5 0

Answer:

20 meters.

Explanation:

Since it went 100 meters in 10 seconds, that means it is going 10 meters per second. In 2 seconds, it must have gone 20 meters, if the speed is constant.

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3.
Alborosie

Answer:

C

Explanation:

Acceleration is defined as a change in velocity over time. This means that as long as the forces are not zero, the velocity should be changing. The can be negative (as this is negative acceleration also known as deceleration) or positive (known as acceleration). It doesn't matter if they are decimals or fractions.

4 0
3 years ago
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PLEASE HELP! How much heat is absorbed by 57g iron skillet when its temperature rises from 11°c to 30°C?
Amiraneli [1.4K]

mass times specific heat times tem change.

57 x sh x (30-11)

convert to mks and look up sh iron

7 0
2 years ago
HELP MEH QUICK PLEASE
lozanna [386]

Answer:

D) a Battery

Explanation:

The best real-life example of direct current is a battery. Batteries have positive and negative terminals on a battery, the electrons in the wires will begin to flow to produce a current.

6 0
2 years ago
Newton's third law states that for every action force there is an equal and opposite reaction force. An idiot in your class says
Otrada [13]
A. Because the third laws say that for every action force the is an equal and opposite reaction force
4 0
2 years ago
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Two coaxial conducting cylindrical shells have equal and opposite charges. The inner shell has charge +q and an outer radius a,
Leviafan [203]

Answer:

\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}

Explanation:

As we know that the charge per unit length of the long cylinder is given as

\lambda = \frac{q}{L}

here we know that the electric field between two cylinders is given by

E = \frac{2k\lambda}{r}

now we know that electric potential and electric field is related to each other as

\Delta V = - \int E.dr

\Delta V = -\int_a^b (\frac{2k\lambda}{r})dr

\Delta V = -2k \lambda ln(\frac{b}{a})

\Delta V = \frac{\lambda ln(\frac{b}{a})}{2\pi \epsilon_0}

\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}

7 0
2 years ago
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