1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
13

The proper length of the first lane of a competitive running track is 400 m (1,312.3 ft). A runner runs track from the starting

line four times, stopping at the starting line.
Which statement is TRUE?

Group of answer choices

The runner's distance is 1600 m, his displacement is 0 m, and his speed is 0 m/s.

The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s.

The runner's displacement is 1600 m, his distance is 0 m, and his velocity is 0 m/s.

The runner's distance and displacement are 1600 m and his velocity cannot be calculated given this information.
Physics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:

The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s.

Explanation:

It is given that,

Length of the truck, l = 400 m

A runner runs track from the starting line four times, stopping at the starting line. In this case, the distance covered by the runner is, 4 l i.e. 4 × 400 m = 1600 meters.

Distance covered by an object is the overall path travelled during its entire journey. So, runner's distance is 1600 meters.

We know that the displacement of an object is equal to the shortest path covered or it is equal to the difference between final position and initial position. As a result, the displacement of runner is 0 as he is coming back to starting line.

We know that the net displacement divided by total time taken is called velocity of an object. So, velocity will be 0.

Hence, the correct option is (b) "The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s".

irakobra [83]3 years ago
4 0

Answer:

The runner's distance is 1600 m, his displacement is 0 m, and his speed is 0 m/s.

Explanation:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. In this case distance is 400m x 4= 1600m. Displacement is a vector quantity that refers to the distance betwen the first and the last position of an object. In this case is 0 because the runer always track in the same place.

Finally, the velocity is 0 m/s because the runner always tracks a point, and in order to measure the velocity we need a distance between to points and a time.

You might be interested in
Thunder is heard 7.2 seconds after a bolt of lightning is observed. if the speed of sound is 349 m/s, how far away did the light
Natasha2012 [34]

Answer:

2512.8 meters

Explanation:

s=d/t

by using speed formula

5 0
2 years ago
Help please! This question is driving me crazy
Varvara68 [4.7K]

Answer:

-10.8°, or 10.8° below the +x axis

Explanation:

The x component of the resultant vector is:

x = 3.14 cos(30.0°) + 2.71 cos(-60.0°)

x = 4.07

The y component of the resultant vector is:

y = 3.14 sin(30.0°) + 2.71 sin(-60.0°)

y = -0.777

Therefore, the angle between the resultant vector and the +x axis is:

θ = atan(y / x)

θ = atan(-0.777 / 4.07)

θ = -10.8°

The angle is -10.8°, or 10.8° below the +x axis.

3 0
4 years ago
Point charges q1 = 14 µC and q2 = −60 µC are fixed at r1 = (5.0î − 4.0ĵ) m and r2 = (9.0î + 7.5ĵ) m. What is the force (in N) of
Lostsunrise [7]

Answer:

The force on q₁ due to q₂ is (0.00973i + 0.02798j) N

Explanation:

F₂₁ = \frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|}

Where;

F₂₁ is the vector force on q₁ due to q₂

K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²

r₂₁ is the unit vector

|r₂₁| is the magnitude of the unit vector

|q₁| is the absolute charge on point charge one

|q₂| is the absolute charge on point charge two

r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)

|r₂₁| = \sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}

(|r₂₁|)² = 148.25

F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }

      = 0.050938(0.19107i + 0.54933j) N

      = (0.00973i + 0.02798j) N

Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N

7 0
3 years ago
What is Agent Object Notation? ( For Force Diagrams. )
kobusy [5.1K]
F sub n is an example.
6 0
3 years ago
What is the definition of permitted orbits ?
givi [52]
.The path of a celestial body or an artificial satellite as it revolves around another body due to their mutual gravitational <span>attraction.</span>
7 0
4 years ago
Other questions:
  • Why do toasters always have a setting that burns the toast to a horrible crisp, which no decent human being would eat?
    13·2 answers
  • Now, a second resistor R2 of 3.3 105 Ω is connected in parallel to the existing resistor in the circuit, and a second capacitor
    13·1 answer
  • If the same net force is applied to a 7 kg object and a 21 kg object, then the 21 kg object accelerates three times faster than
    15·1 answer
  • Two or more different monomers will link to form a
    8·1 answer
  • A person riding in a hot air air balloon basket ascends to 1000 ft above the ground. What happened to the atmospheric pressure a
    5·1 answer
  • A snowball starting at rest rolls down a hill and reaches 5 m/s. If the hill is
    12·1 answer
  • Through which of the following ways can heat be transferred?
    12·2 answers
  • The figure shows the motion of electrons in a wire which is near the North pole of a magnet. The wire will be pushed:
    9·1 answer
  • Which of the following statements best represents a comparison of the two motions shown on the graph?
    8·1 answer
  • PLEASE HELP ME I AM TIMED!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!