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umka21 [38]
3 years ago
13

The proper length of the first lane of a competitive running track is 400 m (1,312.3 ft). A runner runs track from the starting

line four times, stopping at the starting line.
Which statement is TRUE?

Group of answer choices

The runner's distance is 1600 m, his displacement is 0 m, and his speed is 0 m/s.

The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s.

The runner's displacement is 1600 m, his distance is 0 m, and his velocity is 0 m/s.

The runner's distance and displacement are 1600 m and his velocity cannot be calculated given this information.
Physics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:

The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s.

Explanation:

It is given that,

Length of the truck, l = 400 m

A runner runs track from the starting line four times, stopping at the starting line. In this case, the distance covered by the runner is, 4 l i.e. 4 × 400 m = 1600 meters.

Distance covered by an object is the overall path travelled during its entire journey. So, runner's distance is 1600 meters.

We know that the displacement of an object is equal to the shortest path covered or it is equal to the difference between final position and initial position. As a result, the displacement of runner is 0 as he is coming back to starting line.

We know that the net displacement divided by total time taken is called velocity of an object. So, velocity will be 0.

Hence, the correct option is (b) "The runner's distance is 1600 m, his displacement is 0 m, and his velocity is 0 m/s".

irakobra [83]3 years ago
4 0

Answer:

The runner's distance is 1600 m, his displacement is 0 m, and his speed is 0 m/s.

Explanation:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. In this case distance is 400m x 4= 1600m. Displacement is a vector quantity that refers to the distance betwen the first and the last position of an object. In this case is 0 because the runer always track in the same place.

Finally, the velocity is 0 m/s because the runner always tracks a point, and in order to measure the velocity we need a distance between to points and a time.

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We can use the conservation of angular momentum to solve.

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\text{Solid cylinder:} I = \frac{1}{2}MR^2\\\\\text{Object around center:} = MR^2

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\frac{0.17rev}{s} * \frac{2\pi rad}{1 rev} = 1.068 \frac{rad}{s}

According to the above and the given information, we can write an equation and solve for ωf.

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<h3>Relationship between dielectric material and electric field</h3>

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A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite
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Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

       The gravitational force is  F_g  = 6600 \ N

The kinetic energy of the satellite is mathematically represented as

       KE  =  \frac{1}{2} * mv^2

where v is the speed of the satellite which is mathematically represented as

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=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

=>    KE  =  \frac{ 1}{2} *F_g * r

substituting values

       KE  =  \frac{ 1}{2} *6600 * 2.3*10^{7}

         KE  =  7.59  *10^{10} \  J

 

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