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vazorg [7]
3 years ago
7

By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? assume the field is unifo

rm inside the capacitor and zero outside the capacitor.
Physics
1 answer:
Sindrei [870]3 years ago
6 0
 <span>A </span>proton<span> traveling at a speed of 1.0*10^6 m/s enters the gap between the plates of a 2.0 cm wide parallel-plate </span>capacitor.<span> The surface charge densities on the plates are (+-)(positive and negative) 1.1*10^(-6) C/m2.</span><span> ... Physics problem: How </span>far<span> (in m) </span><span>has the proton deflected sideway</span>
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A 2.26 kg book is dropped from a height 1.5m what is its acceleration
Arada [10]
The answer is 9.8 ms^-2, because there is only one force acting on the object so the acceleration will be numerically equal to the gravitational field strength.
4 0
3 years ago
A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a
VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

r_1 = 45 sin15 \hat i + 45 cos15 \hat j

r_1 = 11.64 \hat i + 43.46\hat j

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

r_2 = 30 cos15\hat i + 30 sin15 \hat j

r_2 = 28.98\hat i + 7.76 \hat j

now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

d = 17.34 \hat i - 35.7 \hat j

so the magnitude is given as

d = \sqrt{17.34^2 + 35.7^2}

d = 39.7 km

4 0
3 years ago
What happens when you see something?
Elan Coil [88]
The answer is D light rays shine on an object which then reflects back to our retina
5 0
4 years ago
You plug your microwave into an outlet and then you heat up a piece of pizza in it. This is an example of an...
dem82 [27]

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b

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3 0
3 years ago
Calculate the frequency of the red light emitted by a neon sign with a wavelength of 690 nm
Ne4ueva [31]

Answer:

4.35 \times 10^{14} Hz

Explanation:

The frequency of a light is inversely proportional to its wavelength. It is given by:

f = \frac{v}{\lambda}

The speed of the red light, v = 3.0 × 10⁸ m/s

The wavelength of the red light, λ = 690 nm = 690 ×10⁻⁹ m

f = \frac{3.0 \times 10^8 m/s}{690\times 10^{-9}m} = 4.35 \times 10^{14} Hz

Thus, the frequency of red light emitted by neon sign having wavelength 690 nm is 4.35 \times 10^{14} Hz

7 0
3 years ago
Read 2 more answers
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