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gayaneshka [121]
3 years ago
10

Help Me !! I have an exam.

Physics
2 answers:
kirill115 [55]3 years ago
6 0
Positive i believe:)))
Mumz [18]3 years ago
5 0

Answer:

I think positive...

.....

......

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A 2,500 kg car moves at 15 m/s^2; 15m/s^2 is the (blank) of the car.
Neporo4naja [7]
A. Acceleration.
acceleration is m/s^2. speed is m/s
7 0
3 years ago
A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

8 0
3 years ago
Would the forces acting on the sky diver be balanced or unbalanced? Explain your answer.
docker41 [41]

Answer:

your mom is balanced!!!

4 0
2 years ago
300 Jules energy are used to push an object with a force of 75N. what is the maximum distance the object can move?
Artyom0805 [142]

Energy consumed in doing the work = 300 Joules

Force applied on the object = 75 N

Let the distance moved by the object be d.

Work done by the force is determined by the force applied and the displacement happened in the direction of the force applied.

Work done = Force x displacement

300 = 75 x d

d = \frac{300}{75}

d = 4 m

Hence, the maximum distance moved by the object = 4 meters

6 0
3 years ago
A 55.0-kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. What is the speed of the ball after it
PolarNik [594]

Answer:

The speed of the ball is 9.07 m/s.

Explanation:

Given that,

Mass of the lead ball, m = 55 kg

Height of the tower, h = 55 m

We need to find the speed of the ball it has traveled 4.20 m downward, x = 4.2 meters

The initial speed of the ball will be 0 as it was at rest initially. Let v is the speed of the ball after it has traveled 4.20 m downward. It is a case of equation of motion such that :

v^2-u^2=2ax

v^2=2ax

Here, a = g

v^2=2\times 9.8\times 4.2

v = 9.07 m/s

So, the speed of the ball is 9.07 m/s. Therefore, this is the required solution of given condition.

4 0
3 years ago
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