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3 years ago

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A box of unknown weight is 1 m away from the fulcrum. To balance the sides, a student applies a force of 4 N at a distance of 3

m away from the fulcrum. How much force is the box exerting on the balance beam? In other words, what is the weight of the box?
This is due by 4:10

1 answer:

Solnce55 [7]3 years ago

3 0

Answer: I think A

Explanation:

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Please help :( A ray of laser light strikes a glass surface at an angle θa = 22.5° to the normal. What is the angle θb of the re

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Answer:

Explanation:

We shall apply law of refraction which is as follows

sin i / sinr = μ , where i is angle of incidence , r is angle of refraction and μ is refractive index

here i = θa = 22.5°

r = θb

μ = 1.77

sin22.5 / sinθb = 1.77

.3826 / sinθb = 1.77

sinθb = .216

θb = 12.5 °.

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starting at a position of 0 m, if the man is moving at a constant velocity of 2 m/s, it will take seconds for him to reach a pos

Harman [31]

The calculated time is 6 seconds.

Time is defined by physicists as the flow of events from the past through the present and into the future. In essence, a system is timeless if it is unchanging. When describing events that take place in three-dimensional space, time can be thought of as the fourth dimension of reality. Even if time isn't directly connected to energy, it is undoubtedly connected to many other components of energy. For instance, the movement of energy across the universe can affect the direction of time (from the past to the future).

V= 2 m/s

d=12 m

t=?

we know that velocity=displacement / time

time= displacement / velocity

= 12/2

=6 seconds

the calculated time is 6 seconds.

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Atom A and Atom B have the same number of protons and neutrons, but they do not have the same number of electrons.

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If a boy weighs 490 N and stands on a flat rough surface with a

OleMash [197]

The force of static friction acting on the boy is 333 Newtons.

Hence, option (d) 333N is the correct answer.

Given the data in the question;

Weight of boy; $F_n = 490N$

Coefficient of static friction; $u_s = 0.68$

Force of static friction acting on the boy; $F_s = \ ?$

<h3>Friction</h3>

Friction is simply referred as the resistance an object experience when moving or trying to move over another object. It can either by dynamic or static.

Static friction is the resistance experienced by a body at rest.

Coefficient of friction is the measure of how easily a body moves in relation to the other.

Static friction is expressed as;

$F_s = u_s * F_n$

Where $F_s$ is the normal force and $u_s$ is the coefficient of static friction.

We substitute our given values into the equation above

$F_s = u_s * F_n\\\\F_s = 0.68 * 490N\\\\F_s = 333.2N\\\\F_s = 333N$

The force of static friction acting on the boy is 333 Newtons.

Hence, option (d) 333N is the correct answer.

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2 years ago