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Bess [88]
2 years ago
6

A box of unknown weight is 1 m away from the fulcrum. To balance the sides, a student applies a force of 4 N at a distance of 3

m away from the fulcrum. How much force is the box exerting on the balance beam? In other words, what is the weight of the box?
This is due by 4:10
Physics
1 answer:
Solnce55 [7]2 years ago
3 0

Answer: I think A

Explanation:

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E<br> 3.6 What force is needed to give a mass of<br> 20 kg an acceleration of 5 m/s??
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Explanation:

  • Mass(m)= 20kg
  • Acceleration (a)= 5m/s²
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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

c = 340 m/s

B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

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