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barxatty [35]
2 years ago
9

The reaction below describes cellular respiration. Which compounds are the reactants and which are the products? C6 H12 O6+ 6 O2

+ 6 CO2+ 6 H2O
Chemistry
1 answer:
rjkz [21]2 years ago
6 0

Answer:

C6H12O6 and 6O2 are reactants.

6CO2 and 6H2O are products.

Explanation:

Chemical equation:

C6H12O6 + 6O2 → 6CO2 + 6H2O + ATP

      Reactants                       Products

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration :

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration :

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

Steps involve in anaerobic respiration are:

Glycolysis :

Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.

Fermentation :

The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced, however carbon dioxide is released in this step.

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Select the correct answer. Two charged objects, A and B, exert an electric force on each other. What happens if the distance bet
VikaD [51]

Answer:

The electric force between them decreases

Explanation:

The force between two charged particle is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

r is the distance between charges

If the distance between the charges is increased, the electric force gets decreased as there is an inverse relation between force and distance.

Hence, the correct option is (c) "The electric force between them decreases"

7 0
2 years ago
A tank of oxygen with a pressure of 23 atm is moved from room temperature of 293K to a storage freezer at 239K. What is the fina
Gelneren [198K]

Answer:

18.76atm

Explanation:

Using the formula V1P1/T1 = V2P2/T2, from combined gas law. Volume is constant since we have not been given. Therefore the formula comes to be; P1/T1 = P2/T1

To get P2 = T2(P1/T1)

Where P2 is final pressure

P2 = 239K ( 23atm/293K)

=18.76atm

7 0
3 years ago
12. How much mass is in a 3.25-mole sample of NH 4 OH? A. 10.8 g B. 34.0 g C. 35.1 g D. 114 g
Galina-37 [17]

Answer:

D. 114 g

Explanation:

  • NH4OH molecular weight. Molar mass of NH4OH = 35.0458 g/mol This compound is also known as Ammonium Hydroxide.
  • Convert grams NH4OH to moles or moles NH4OH to grams. Molecular weight calculation: 14.0067 + 1.00794*4 + 15.9994 + 1.00794.
8 0
3 years ago
What is the volume of 0.120 g of C2H2F4<br> vapor at 0.970 atm and 22.4°C?<br> Answer in units of L.
ludmilkaskok [199]

Answer:

V= 0.031L

Explanation:

P= 0.97atm, V= ?, n= 0.12/98 =0.00122mol, R= 0.082, T= 22.4+273= 295.4

Applying

PV=nRT

0.970×V = 0.00122×0.082×295.4

Simplify the above equation

V= 0.031L

6 0
2 years ago
A sample of a compound of xenon and fluorine contains molecules of a single type; XeFn, where n is a whole number. If 5.0 x 1020
kicyunya [14]

Answer:

4

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

N_a=6.023\times 10^{23}

Hence,

Mass of XeF_n = 131.293+ n18.998 g

So,

6.023\times 10^{23}  molecules have a mass of 131.293+ n18.998 g

Also,

1  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}} g

So,

5.0\times 10^{20}  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20} g

Also, given mass = 0.172 g

Thus,

\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}=0.172

\frac{18.998n+131.293}{1204.6}=0.172

18.998n+131.293=207.1912

n=\frac{75.8982}{18.998}=4

<u>Thus, value of n is 4.</u>

4 0
2 years ago
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