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SashulF [63]
3 years ago
6

Which of the following solutions is a good buffer system? Which of the following solutions is a good buffer system? a solution t

hat is 0.10 M HF and 0.10 M LiC2H3O2 a solution that is 0.10 M HC2H3O2 and 0.10 M LiC2H3O2 a solution that is 0.10 M LiOH and 0.10 M KOH a solution that is 0.10 M HF and 0.10 M NH4+ None of the above is a buffer system.
Chemistry
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

A solution that is 0.10 M HC2H3O2 and 0.10 M LiC2H3O2 is a good buffer system.

Explanation:

A buffer is defined as the mixture between a weak acid and its conjugate base or vice versa.

For the solutions:

0.10 M HF and 0.10 M LiC2H3O2. HF is a weak acid but LiC2H3O2 is the conjugate base of the weak acid (HC2H3O2, acetic acid).

0.10 M HC2H3O2 and 0.10 M LiC2H3O2. Here, you have a mixture of HC2H3O2, acetic acid, weak acid, and LiC2H3O2 is its conjugate base. Thus, <em>this is a good buffer system</em>

<em></em>

0.10 M LiOH and 0.10 M KOH. LiOH ans KOH are both strong bases.

0.10 M HF and 0.10 M NH4+. Again, HF is a weak acid but NH4+ is the conjugate acid of a weak base (NH3).

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A sample of nitrogen gas is at a temperature of 50 c and a pressure of 2 atm. If the volume of the sample remains constant and t
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Answer:

The new temperature of the nitrogen gas is 516.8 K or 243.8 C.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Where P = pressure, T = temperature, K = Constant

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 2 atm
  • T1= 50 C= 323 K (being 0 C= 273 K)
  • P2= 3.2 atm
  • T2= ?

Replacing:

\frac{2 atm}{323 K} =\frac{3.2 atm}{T2}

Solving:

T2*\frac{2 atm}{323 K} =3.2 atm

T2=3.2 atm*\frac{323 K}{2 atm}

T2= 516.8 K= 243.8 C

<u><em>The new temperature of the nitrogen gas is 516.8 K or 243.8 C.</em></u>

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2 years ago
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