A 55 kg block of ice slides down a frictionless ramp that is 2.0 m long and 0.91 m high. A worker pushes up against the ice, par
allel to the ramp, so that the block slides down the ramp at constant speed. a. Find the force exerted by the worker.
1 answer:
Answer:
223.4N
Explanation:
Hello!
To solve this problem follow the steps below, the complete procedure is in the attached image
1. draw a complete outline of the problem involving forces and geometries
2. Find the angle of the ramp using the tangent function
3. Find the component parallel to the ice block weight ramp using the sine function. Remember that the magnitude of the weight is the product of mass and acceleration.
4. For a body to move with constant speed its acceleration must be zero, remembering the second law of Newton's movement: force is equal to the product of mass and acceleration. we infer that the sum of the forces in the direction parallel to the ramp must be zero.
whereby the force that the worker makes is equal to the component of the weight of the ice block in the direction of the ramp.
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The y-component of the acceleration is
Explanation:
The y-component of the acceleration is given by:
where
is the y-component of the final velocity
is the y-component of the initial velocity
t is the time elapsed
For the ice skater in this problem, we have:
where
u = 2.25 m/s is the initial velocity
is the initial direction
, where
v = 4.65 m/s is the final velocity
is the final direction
The time elapsed is
t = 8.33 s
Therefore, we can find the y-component of the acceleration:
Learn more about acceleration:
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Answer:
(e)
Explanation:
At resonance we know that
That is
We have given resonance frequency f =4511 Hz and inductance L=1.82 mH
So
So option e is the correct answer