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Sloan [31]
3 years ago
8

A 55 kg block of ice slides down a frictionless ramp that is 2.0 m long and 0.91 m high. A worker pushes up against the ice, par

allel to the ramp, so that the block slides down the ramp at constant speed. a. Find the force exerted by the worker.

Physics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

223.4N

Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem involving forces and geometries

2. Find the angle of the ramp using the tangent function

3. Find the component parallel to the ice block weight ramp using the sine function. Remember that the magnitude of the weight is the product of mass and acceleration.

4. For a body to move with constant speed its acceleration must be zero, remembering the second law of Newton's movement: force is equal to the product of mass and acceleration. we infer that the sum of the forces in the direction parallel to the ramp must be zero.

whereby the force that the worker makes is equal to the component of the weight of the ice block in the direction of the ramp.

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Solve the equation 3x^2+8x+5=0
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3x^2+8x+5=0\\
3x^2+3x+5x+5=0\\
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4 0
3 years ago
Wo siblings are arguing over what way to pull a 10 kg wagon. Boris wants to pull it to the right. Boris puts 220 N of force on t
Mrrafil [7]

Answer:

a) Then net force acting on the wagon  30 [N] in a negative direction to the left

b)Acceleration of the wagon 3 m/s² in a negative direction to the left

Explanation:

The coordinates x and y show the positive direction in x-axis ( to the right) and negative direction to the left. In north-south direction positive y values are to the north and negative values to the south

The free-body diagram shows 4 forces acting

In y-axis:

The weight ( P = m*g =  10 [kg]*9,8 [m/s²] = 98 [N] negative

Normal reaction force  Fn = P = 98 [N]  positive ( surface is frictionless)

∑Fy = 0     P - Fn = 0     P = Fn  = 98 [N]

In x-axis:

Boris pulling force to the right (positive ) 220 [N]

Natasha pulling force to the left ( negative) 250 [N]

∑Fx = m*a

220 [N] - 250 [N]  = 10 Kg * a                      [N] = Kg * m /s²

-30 [kg*m/s²]  = 10 * Kg * a

-30/10  =  - 3  m/s²  = a

Sign (-) means the direction of acceleration vector is to the left (the same direction of the movement )

Then net force acting on the wagon  30 [N] in negative direction to the left

Acceleration of the wagon 3 m/s² in negative direction to the left

5 0
3 years ago
Mathphys :( im sorry i annoy you
Vitek1552 [10]

Answer:

4. 7.59276

Explanation:

Add up the x components:

Aₓ + Bₓ + Cₓ = 5 − 1.6 + 2.4 = 5.8

Add up the y components:

Aᵧ + Bᵧ + Cᵧ = -2.4 + 3.3 + 4 = 4.9

Use Pythagorean theorem to find the magnitude:

√(x² + y²)

√(5.8² + 4.9²)

√57.65

7.59276

3 0
3 years ago
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You walk east for 10m then turn north 15m what is your displacementm
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