A 55 kg block of ice slides down a frictionless ramp that is 2.0 m long and 0.91 m high. A worker pushes up against the ice, par
allel to the ramp, so that the block slides down the ramp at constant speed. a. Find the force exerted by the worker.
1 answer:
Answer:
223.4N
Explanation:
Hello!
To solve this problem follow the steps below, the complete procedure is in the attached image
1. draw a complete outline of the problem involving forces and geometries
2. Find the angle of the ramp using the tangent function
3. Find the component parallel to the ice block weight ramp using the sine function. Remember that the magnitude of the weight is the product of mass and acceleration.
4. For a body to move with constant speed its acceleration must be zero, remembering the second law of Newton's movement: force is equal to the product of mass and acceleration. we infer that the sum of the forces in the direction parallel to the ramp must be zero.
whereby the force that the worker makes is equal to the component of the weight of the ice block in the direction of the ramp.
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1. -23.2 J
The gravitational potential energy of the ball is given by
where
m = 1.1 kg is the mass of the ball
g = 9.8 m/s^2 is the acceleration of gravity
h is the height of the ball, relative to the reference point chosen
In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is
h = -2.16 m
And the gravitational potential energy is
2. 41.1 J
Again, the gravitational potential energy of the ball is given by
In this part of the problem, the reference point is the floor.
The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:
h = 5.97 m - 2.16 m = 3.81 m
And so the gravitational potential energy of the ball relative to the floor is
3. 0 J
As before, the gravitational potential energy of the ball is given by
Here the reference point is a point at the same elevation of the ball.
This means that the heigth of the ball relative to that point is zero:
h = 0 m
And so the gravitational potential energy is
Answer:
9.82 × Hz
Explanation:
De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:
λ =
where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.
Given that: h = 6.63 × Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;
λ =
=
=
= 9.8222 ×
The wavelength of the object is 9.82 × Hz.