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Sloan [31]
3 years ago
8

A 55 kg block of ice slides down a frictionless ramp that is 2.0 m long and 0.91 m high. A worker pushes up against the ice, par

allel to the ramp, so that the block slides down the ramp at constant speed. a. Find the force exerted by the worker.

Physics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

223.4N

Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem involving forces and geometries

2. Find the angle of the ramp using the tangent function

3. Find the component parallel to the ice block weight ramp using the sine function. Remember that the magnitude of the weight is the product of mass and acceleration.

4. For a body to move with constant speed its acceleration must be zero, remembering the second law of Newton's movement: force is equal to the product of mass and acceleration. we infer that the sum of the forces in the direction parallel to the ramp must be zero.

whereby the force that the worker makes is equal to the component of the weight of the ice block in the direction of the ramp.

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A well-insulated bucket of negligible heat capacity contains 129 g of ice at 0°C.
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Explanation:

In the following question we are provided with

Mass of the ice M_{i} = 129 g = 0.129 kg

Mass of the steam M_s = 19 g = 0.019 kg

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Temperature of  steam  T_s = 100°C

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The energy been released when the steam changes to water is mathematically given as

            Q_B = M_s * L_v

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                 Q_C = M_s *C_water (100°C)

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             Q_B + Q_C > Q_A

What this means is that the ice will melt

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        Q_B + M_s *C_{water}(100-T) = Q_A + M_i C_{water} T

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                                              T = 12.48^oC

       

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