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Sloan [31]
3 years ago
8

A 55 kg block of ice slides down a frictionless ramp that is 2.0 m long and 0.91 m high. A worker pushes up against the ice, par

allel to the ramp, so that the block slides down the ramp at constant speed. a. Find the force exerted by the worker.

Physics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

223.4N

Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem involving forces and geometries

2. Find the angle of the ramp using the tangent function

3. Find the component parallel to the ice block weight ramp using the sine function. Remember that the magnitude of the weight is the product of mass and acceleration.

4. For a body to move with constant speed its acceleration must be zero, remembering the second law of Newton's movement: force is equal to the product of mass and acceleration. we infer that the sum of the forces in the direction parallel to the ramp must be zero.

whereby the force that the worker makes is equal to the component of the weight of the ice block in the direction of the ramp.

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Four people are spaced at different distances from where a dog is barking. The barking will sound the loudest to the person who
Volgvan

Answer:

Closest to the dog.

Explanation:

Sounds are louder the closer you are to them.

6 0
3 years ago
Gauss's law: Group of answer choices can always be used to calculate the electric field. relates the electric field throughout s
kvasek [131]

Answer:

relates the electric field at points on a closed surface to the net charge enclosed by that surface.

Explanation:

Gauss Law states that overall electric flux of a closed surface is equivalent right to charge enclosed which is divided by the permittivity. In other words Gauss Law stress that

net electric flux that pass through an hypothetical closed surface is equivalent to overall electric charge present within that closed surface.

The Gauss law can be expressed mathematically as

ϕ = (Q/ϵ0)

Q = total charge within the surface,

ε0 = the electric constant

5 0
3 years ago
Need help with this plz
Lisa [10]

Answer:

1 - amplification

3- actinide

5 - radioactive decay ( im not really sure on this one )

7- alternating current

Explanation:

7 0
3 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component
Bond [772]

The y-component of the acceleration is 0.33 m/s^2

Explanation:

The y-component of the acceleration is given by:

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the  final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

u_y = u sin \theta_1 = (2.25 m/s)(sin 50.0^{\circ})=1.72 m/s

where

u = 2.25 m/s is the initial velocity

\theta_1 = 50.0^{\circ} is the initial  direction

v_y = v sin \theta_2 = (4.65)(sin 120^{\circ})=4.03 m/s, where

v = 4.65 m/s is the final velocity

\theta_2 = 120.0^{\circ} is the final direction

The time elapsed is

t = 8.33 s

Therefore, we can find the y-component of the acceleration:

a_y=\frac{4.03-1.72}{8.33}=0.33 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0
3 years ago
A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor
OLEGan [10]

Answer:

(e)6.835\times 10^{-7}F

Explanation:

At resonance we know that X_l=X_C

That is \omega L=\frac{1}{\omega C}

\omega ^2=\frac{1}{LC}

\omega =\frac{1}{\sqrt{LC}}

f=\frac{1}{2\pi \sqrt{LC}}

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So 4511=\frac{1}{2\pi \sqrt{LC}}

LC=\frac{1}{4\pi ^2\times 4511^2}

LC=1.244\times 10^{-9}

C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F

So option e is the correct answer

3 0
3 years ago
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