Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
I think you do 120 divided by 5, but I could be wrong.
The coefficient of these two number are -24 and 7. :)
Answer:
The point-slope formula states:
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Where
m
is the slope and
(
x
1
y
1
)
is a point the line passes through.
Substituting the slope and values from the point in the problem gives:
(
y
−
−
1
)
=
3
5
(
x
−
−
3
)
(
y
+
1
)
=
3
5
(
x
+
3
)
If you want the equation in the somewhat more familiar slope-intercept form we can solve this equation for
y
. The slope-intercept form of a linear equation is:
y
=
m
x
+
b
Where
m
is the slope and
b
is the y-intercept value.
y
+
1
=
(
3
5
⋅
x
)
+
(
3
5
⋅
3
)
y
+
1
=
3
5
x
+
9
5
y
+
1
−
1
=
3
5
x
+
9
5
−
1
y
+
0
=
3
5
x
+
9
5
−
5
5
y
=
3
5
x
+
4
5
The point-slope formula states:
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Where
m
is the slope and
(
x
1
y
1
)
is a point the line passes through.
Substituting the slope and values from the point in the problem gives:
(
y
−
−
1
)
=
3
5
(
x
−
−
3
)
(
y
+
1
)
=
3
5
(
x
+
3
)
If you want the equation in the somewhat more familiar slope-intercept form we can solve this equation for
y
. The slope-intercept form of a linear equation is:
y
=
m
x
+
b
Where
m
is the slope and
b
is the y-intercept value.
y
+
1
=
(
3
5
⋅
x
)
+
(
3
5
⋅
3
)
y
+
1
=
3
5
x
+
9
5
y
+
1
−
1
=
3
5
x
+
9
5
−
1
y
+
0
=
3
5
x
+
9
5
−
5
5
y
=
3
5
x
+
4
5
Step-by-step explanation:
