1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tpy6a [65]
3 years ago
12

Why we are not allowed to connect ideal voltage sources in parallel

Physics
1 answer:
deff fn [24]3 years ago
3 0
<span>.when 2 elements are connected in a parallel connection the voltage across them must be same

</span><span>when 2 voltage sources are connected they must have same potential difference across them which is not possible unless they are of same value and in the other case(different value sources) it is same as the greater valued voltage source since it overtakes the other one
</span>
Which means that there is no use in connecting both of them in parallel

hope this helps
You might be interested in
A wheelchair ramp is 5.2 m long and 0.8 m high. Calculate the ramp’s mechanical advantage
Arlecino [84]

Answer:

5

Explanation:

62

3 0
3 years ago
The length of a simple pendulum is 0.81 mand the mass of the particle (the "bob") at the end of the cable is0.23 kg. The pendulu
Gemiola [76]

Answer:

\displaystyle w=3.478\ rad/sec

M=0.0182\ J

v=0.398\ m/s

Explanation:

<u>Simple Pendulum</u>

It's a simple device constructed with a mass (bob) tied to the end of an inextensible rope of length L and let swing back and forth at small angles. The movement is referred to as Simple Harmonic Motion (SHM).

(a) The angular frequency of the motion is computed as

\displaystyle w=\sqrt{\frac{g}{L}}

We have the length of the pendulum is L=0.81 meters, then we have

\displaystyle w=\sqrt{\frac{9.8}{0.81}}

\displaystyle w=3.478\ rad/sec

(b) The total mechanical energy is computed as the sum of the kinetic energy K and the potential energy U. At its highest point, the kinetic energy is zero, so the mechanical energy is pure potential energy, which is computed as

U=mgh

where h is measured to the reference level (the lowest point). Please check the figure below, to see the desired height is denoted as Y. We know that

H+Y=L

And

H=L\ cos\alpha

Solving for Y

Y=L(1-cos\alpha )

Since\ \alpha=8.1^o, L=0.81\ m

Y=0.0081\ m

The potential energy is

U=mgh=0.23\ kg(9.8\ m/s^2)(0.0081\ m)

U=0.0182\ J

The mechanical energy is, then

M=K+U=0+U=U

M=0.0182\ J

(c) The maximum speed is achieved when it passes through the lowest point (the reference for h=0), so the mechanical energy becomes all kinetic energy (K). We know

\displaystyle K=\frac{mv^2}{2}

Equating to the mechanical energy of the system (M)

\displaystyle \frac{mv^2}{2}=0.0182

Solving for v

\displaystyle v=\sqrt{\frac{(2)(0.0182)}{0.23}}

v=0.398\ m/s

4 0
3 years ago
You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
Andru [333]

Answer:

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

v = velocity of the ball at time t.

Placing the origin at the throwing point, y0 = 0.

Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t²     (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Have a nice day!

4 0
4 years ago
What are the difference between conductor and insulator? ​
Anvisha [2.4K]

Answer:

  • A conductor allows energy e.g. electric charge or heat to pass through it easily. While an insulator does not let electric current or heat to travel through it.
  • Insulators have strong molecular bonds. While molecular bonds are very weak in conductors.
  • Insulators have very low conductivity. While in conductors, it is very high.
  • Insulators have a very high resistance and therefore the electrons are held together very firmly. The conductors, on the other hand, have a very low resistance.
  • Insulators do not have any electric field, neither inside nor on the surface. While in conductors, it is found on the surface and continues to be zero in the inner part of the conductor.
5 0
3 years ago
What are the two factors that determine a material's density?
Juliette [100K]
Mass and volume are the 2 factors to determine density
3 0
4 years ago
Other questions:
  • A velocity-time graph is shown below: (2 points)
    7·1 answer
  • Many household products we consider necessary today such as AM and FM radios, televisions, wireless networks, cordless and cellu
    14·2 answers
  • A car with s mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve h
    6·2 answers
  • A 269-turn solenoid is 102 cm long and has a radius of 2.3 cm. It carries a current of 3.9 A. What is the magnetic field inside
    9·1 answer
  • An electric current is created in a long thin wire. How will increasing the current and changing the direction of the current ef
    14·2 answers
  • Refer to Activity 1: Describe the difference between the rate of diffusion seen for urea and albumin
    12·1 answer
  • How can velocity change even if speed stays the same?​
    8·1 answer
  • Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th
    7·1 answer
  • Complete the sentence. The universal solvent is ______ .
    13·2 answers
  • A man is 6ft tall. What is the smallest size plane mirror he can use to see his entire image.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!