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3 years ago

What are the difference between conductor and insulator?

Physics

1 answer:

Anvisha [2.4K]3 years ago

5 0

Answer:

A conductor allows energy e.g. electric charge or heat to pass through it easily. While an insulator does not let electric current or heat to travel through it.
Insulators have strong molecular bonds. While molecular bonds are very weak in conductors.
Insulators have very low conductivity. While in conductors, it is very high.
Insulators have a very high resistance and therefore the electrons are held together very firmly. The conductors, on the other hand, have a very low resistance.
Insulators do not have any electric field, neither inside nor on the surface. While in conductors, it is found on the surface and continues to be zero in the inner part of the conductor.

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Answer:

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Explanation:

The magnetic field is:

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R = radius = 2.4 cm = 0.024 m

r = distance = 0.72 cm = 7.2x10⁻³m

Replacing:

$B=(\frac{4\pi x10^{-7} *3}{2\pi *0.024^{2} } )*7.2x10^{-3}= 7.49x10^{-6} T$

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3 years ago

A raindrop falls to the ground from a rain cloud at an altitude of 3000 meters.

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Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:

D=0.5at where d is distance, a is acceleration and t is time

D is 300 meters

a is 9.8 meter/sec squared

Solve for t in seconds

t = 61.2 seconds

v=at where v is velocity

a is 9.8 meters per second squared

t is 61.2 seconds

solve for v

v = 600 meters per second.

If it had an initial vertical velocity (v0) at the start :

d= 0.5at+v0t

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3 years ago

The charge entering the positive terminal of an element is q = 5 sin 4πt mC while the voltage across the element (plus to minus)

Artemon [7]

Answer:

(a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

Explanation:

Given that,

Charge $q=5\sin4\pi t\ mC$

Voltage $v=3\cos4\pi t\ V$

Time t = 0.3 sec

We need to calculate the current

Using formula of current

$i(t)=\dfrac{dq}{dt}$

Put the value of charge

$i(t)=\dfrac{d}{dt}(5\sin4\pi t)$

$i(t)=5\times4\pi\cos4\pi t$

$i(t)=20\pi\cos4\pi t$

(a).We need to calculate the power delivered to the element

Using formula of power

$p(t)=v(t)\times i(t)$

Put the value into the formula

$p(t)=3\cos4\pi t\times20\pi\cos4\pi t$

$p(t)=60\pi\times10^{-3}\cos^2(4\pi t)$

$p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi t}{2})$

Put the value of t

$p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi\times0.3}{2})$

$p(t)=30\pi\times10^{-3}(1+\cos8\pi \times0.3)$

$p(t)=187.68\ mW$

(b). We need to calculate the energy delivered to the element between 0 and 0.6 s

Using formula of energy

$E(t)=\int_{0}^{t}{p(t)dt}$

Put the value into the formula

$E(t)=\int_{0}^{0.6}{30\pi\times10^{-3}(1+\cos8\pi \times t)}$

$E(t)=30\pi\times10^{-3}\int_{0}^{0.6}{1+\cos8\pi \times t}$

$E(t)=30\pi\times10^{-3}(t+\dfrac{\sin8\pi t}{8\pi})_{0}^{0.6}$

$E(t)=30\pi\times10^{-3}(0.6+\dfrac{\sin8\pi\times0.6}{8\pi}-0-0)$

$E(t)=57.52\ mJ$

Hence, (a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

6 0

3 years ago

6. A 73-kg woman stands on a scale in an elevator. The

olga nikolaevna [1]

Answer:

Explanation:

n = m(g +a)

n= normal force (N)

m=mass (kg)

g=acceleration of gravity

a= acceleration of elevator

rearrange:

a= n/m - g

a= (810 N/73 kg) - 9.8 m/s ^2

a= 1.3 m/s ^2 up

and the acceleration is upwards bc her weight is less than the scale reading

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3 years ago

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 98.9 V/m . Calculate the intensity ???? of this

Pani-rosa [81]

Answer:

$intensity = 12.98 W/m^2$

$Energy = 3.93 J$

Explanation:

As we know that the magnitude of electric field intensity is given as

$E = 98.9 V/m$

now we know that intensity of the wave is given as the product of energy density and speed of the wave

$intensity = \frac{1}{2}\epsilon_0 E^2 c$

$intensity = \frac{1}{2}(8.85 \times 10^{-12})(98.9)^2(3\times 10^8)$

$intensity = 12.98 W/m^2$

so intensity is the energy flow per unit area per unit of time

so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as

$Energy = Area \times time \times intensity$

$Energy = 0.0259(11.7)(12.98)$

$Energy = 3.93 J$

7 0

3 years ago

What are the difference between conductor and insulator? ​

What are the difference between conductor and insulator?