Answer:
The ratio of the orbital time periods of A and B is 
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:

where
R = Radius of the orbit
Now,
For satellite A:

Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):

O is an element (Oxygen) and H2O2 is a compound (Hydrogen Peroxide)
Answer:
200 km/h
Explanation:
Because the train is travelling 1000 km in 5 hours, you simply divide 1000 by 5, giving you 200 km/h. This is about 124.27 mph.
Answer:
3054.32618 rad/s²
-431.1989 rad/s²
29080
Explanation:
Converting angular speed to rad/s


The average acceleration while speeding up is 3054.32618 rad/s²
The number of turns in the 1.2 seconds

The number of rotations in the 1.2 seconds is 349.99
Number of rotations in the 45 seconds


Average angular acceleration while slowing down -431.1989 rad/s²

Number of rotations while slowing down is 2479.16718
Total number of rotations is 349.99+26250+2479.16718 = 29079.15718 = 29080
<span>The answers are --
a) wind direction
b) wind speed
e) intensity of precipitation
f) location of precipitation</span>