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3 years ago

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Chemistry

2 answers:

IgorC [24]3 years ago

5 0

Answer:8.31

Explanation:

Marianna [84]3 years ago

3 0

Answer: 0.082 atm L k^-1 mole^-1

Explanation:

Given that:

Volume of gas (V) = 62.0 L

Temperature of gas (T) = 100°C

Convert 100°C to Kelvin by adding 273

(100°C + 273 = 373K)

Pressure of gas (P) = 250 kPa

[Convert pressure in kilopascal to atmospheres

101.325 kPa = 1 atm

250 kPa = 250/101.325 = 2.467 atm]

Number of moles (n) = 5.00 moles

Gas constant (R) = ?

To get the gas constant, apply the formula for ideal gas equation

pV = nRT

2.467 atm x 62.0L = 5.00 moles x R x 373K

152.954 atm•L = 1865 K•mole x R

To get the value of R, divide both sides by 1865 K•mole

152.954 atm•L / 1865 K•mole = 1865 K•mole•R / 1865 K•mole

0.082 atm•L•K^-1•mole^-1 = R

Thus, the value of gas constant is 0.082 atm L k^-1 mole^-1

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Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant

Elina [12.6K]

Excess reactant : Na

NaCl produced : = 16.497 g

<h3>Further explanation</h3>

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Cl₂

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Cl₂(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Cl₂ = 0.141 : 1 = 0.141

Limiting reactant : Cl₂(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

= 2/1 x mol Cl₂

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

4 0

2 years ago

Solid potassium chlorate decomposes upon heating to form

olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

$\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

V2 = $\frac{P1V1T2}{T1P2}$

V2 = 664.1052 ml

245.2 yielded 67.2 molar volume of oxygen

0.66411 will yield = $\frac{245.2 * 0.66411}{67.2}$ = 2.4232 g

percentage of potassium chlorate in the original mixture = $\frac{2.4232 * 100}{7.44}$ = 32.6%

3 0

3 years ago

At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution

IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = $x_{A}\times P_{A}^{0}$

vapour pressure of a component (B) in solution = $x_{B}\times P_{B}^{0}$

Where $x_{A},x_{B}$ are mole fraction of component A and B in solution respectively

$P_{A}^{0},P_{B}^{0}$ are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = $0.340\times 745 torr$

= 253 torr

7 0

3 years ago

What is the mass of silver in 4.3g AgNO3?

gregori [183]

4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag

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3 years ago

An element is to a __ as an organ is to a ___

Vera_Pavlovna [14]

Answer:

An element is to a compound as an organ is to tissue

Explanation:

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3 years ago