Question

5/10

Answer 1

Answer:8.31

Explanation:

Answer 2

Answer: 0.082 atm L k^-1 mole^-1

Explanation:

Given that:

Volume of gas (V) = 62.0 L

Temperature of gas (T) = 100°C

Convert 100°C to Kelvin by adding 273

(100°C + 273 = 373K)

Pressure of gas (P) = 250 kPa

[Convert pressure in kilopascal to atmospheres

101.325 kPa = 1 atm

250 kPa = 250/101.325 = 2.467 atm]

Number of moles (n) = 5.00 moles

Gas constant (R) = ?

To get the gas constant, apply the formula for ideal gas equation

pV = nRT

2.467 atm x 62.0L = 5.00 moles x R x 373K

152.954 atm•L = 1865 K•mole x R

To get the value of R, divide both sides by 1865 K•mole

152.954 atm•L / 1865 K•mole = 1865 K•mole•R / 1865 K•mole

0.082 atm•L•K^-1•mole^-1 = R

Thus, the value of gas constant is 0.082 atm L k^-1 mole^-1