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zlopas [31]
3 years ago
13

The following reactions take place in the ozone layer by the absorption of ultraviolet light.

Chemistry
1 answer:
____ [38]3 years ago
5 0

Answer:

Option B will require a shorter wave length of light.

Explanation:

The bonding between Ozone (O3) and Oxygen (O2) can be used to explain why the breaking of oxygen into Oxygen radicals will require a shorter wave length.

  • The bond between Oxygen (O2) is a double bond while Ozone (O3) has an intermediate bond between a double bond and a single bond.
  • The bond order of Oxygen (O2) is equals 2 while that of Ozone (O3) is 1.5. Since the bond order of oxygen is higher, it will require more energy to break the bond compared to breaking the Ozone (O3) bond.
  • Recall that Energy is inversely proportional to wave length.
  • So it will require a shorter wave length to break the Oxygen (O2) into its radicals.
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irozion

Explanation:

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Is one mole of zinc the same as one atom of zinc?
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Answer: No.

Explanation: One mole of zinc is not the same as one atom of zinc. In one mole of zinc, there are approximately 6.022*10^23 atoms of zinc.

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In which block of the periodic table is uranium (U) found?
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Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

5 0
3 years ago
For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an excepti
Maksim231197 [3]

Answer:

0,0,0,0

Explanation:

The formal charge formula:

Formal charge= Valence electrons - lone pair electrons - 0.5 shared electrons

So:

Hydrogen: 1 elec. of valence and shares two electrons with the O

Formal charge= 1 - 0 - 0.5*2=0

Oxygen: 6 elec. of valence, 2 lone pairs and shares two electrons with the H and two with the F

Formal charge= 6 - 4 - 0.5*4=0

Fluorine: 7 elec. of valence, 6 lone pairs and shares two electrons with the O

Formal charge= 7 - 6 - 0.5*2=0

Oxygen: 6 elec. of valence, 3 lone pairs

Formal charge= 6 - 6 - 0.5*0=0

Note: the dative bond between F and the second O doesn't count as shared electrons.

8 0
3 years ago
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