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3 years ago

What is the range of this relation (2,-3),(-4,2),(6,2),(-5,-3),(-3,0)

Mathematics

2 answers:

maxonik [38]3 years ago

7 0

Answer:

Range of this relation = -3, 2

Step-by-step explanation:

We are given the following relation and we are to find its range:

$(2,-3),(-4,2),(6,2),(-5,-3),(-3,0)$

The set of all the possible dependent values a relation can produce from its values of domain are called its range. In simple words, it is the list of all possible inputs (without repeating any numbers).

Therefore, the range of this relation is: -3, 2

viva [34]3 years ago

4 0

Answer: $Range:$ { $-3,0,2$ }

Step-by-step explanation:

The range of a relation is the set of y-coordinates of the ordered pairs (These are the second numbers of each ordered pair).

In this case you have the following relation:

$(2,-3),(-4,2),(6,2),(-5,-3),(-3,0)$

Therefore, based on the explained bofore, you can conclude that the rsnge of the given relation is the following:

$Range:$ { $-3,0,2$ }

(Notice that you do not need to write the same number twice)

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Eric took out an 80/20 mortgage to buy a house costing $175,000. The first (80%) mortgage has an interest rate of 4.75%, and the

Serhud [2]

Answer:

The total monthly mortgage payment for the house is $975.63

Step-by-step explanation:

The principle amount is $175000

80% of 175000 is = $0.8\times175000$ = $140000

20% of 175000 is = $0.2\times175000$ = $35000

Emi formula is :

$\frac{p\times r\times(1+r)^{n} }{(1+r)^{n}-1 }$

For 1st part:

p = 140000

r = 4.75/12/100=0.00395

n = $30*12=360$

Putting values in formula we get

$\frac{140000\times0.00395\times(1.00395)^{360} }{(1.00395)^{360}-1 }$

= $729.508

For 2nd part:

p = 35000

r = 7.525/12/100=0.00627

n = $30*12=360$

Putting values in formula we get

$\frac{35000\times0.00627\times(1.00627)^{360} }{(1.00627)^{360}-1 }$

= $245.301

Adding both the monthly payments:

$729.508+245.301=974.809$ dollars

This is closest to option A.

So, option A is the answer.

And for 30 years the mortgage payment will be =

$975.63\times12\times30=351226.80$ dollars

5 0

3 years ago

Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the

stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

$d = -33-(-15)$

$d = -33+15$

$d = -18$

Now, nth term of an arithmetic sequence is

$a_n=a+(n-1)d$

Substitute a=-15 and d=-18.

$a_n=-15+(n-1)(-18)$

$a_n=-15-18n+18$

$a_n=-18n+3$

Therefore, the nth term of the given arithmetic sequence is $a_n=-18n+3$ .

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3 years ago

Someone please help me with this geometry question

marin [14]

Answer:

Step-by-step explanation:

-7x + 12 + (-8x + 48) = 180

-15x + 60 = 180

-15x = 120

x = -8

m<BDC= -7(-8)+ 12 = 56 + 12 = 68

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2 years ago

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grandymaker [24]

Answer:

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Step-by-step explanation:

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2 years ago

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kvasek [131]

Answer:

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Step-by-step explanation:

Rewrite these equations as

y = (1/2)x + 1

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3 years ago