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>(7.5 * 10^23) molecules / (6.022 * 10^23 molecules / mole) = 1.2 mol H2SO4 Third multiply moles H2SO4 by molar mass of H2SO4.<
<span> It showed that the atom contains a small dense nucleus. The reason why this can be concluded is that the experiment showed that alpha particles can for the most part pass right through the foil. This showed that the nucleus of the atom is very small and takes up a very small portion of the size of an atom since the nucleus is what would reflect the alpha particle. If atoms were not mostly empty space, the alpha particles would have been bounced back and the opposite of what was observed would have happened (all or at least the majority would be bounced back instead the majority getting through with only a small portion being reflected back).
I hope this helps. Let me know in the comments if anything is unclear.</span>
Uranium provides nuclear fuel used generate electricity in nuclear power station,also used by the military to power nuclear submarines and in nuclear weapons.
Answer:
Explanation:
From the given information:
The energy of photons can be determined by using the formula:
where;
planck's constant (h) =
speed oflight (c) =
wavelength λ = 58.4 nm
To convert the energy of photon to (eV), we have:
Hence
E = 21.2 eV
b)
The equation that illustrates the process relating to the first ionization is:
c)
The 1st ionization energy (I.E) of Hg can be calculated as follows:
Recall that:
I.E = Initial energy - Kinetic Energy
I₁ (eV) = 21.2 eV - 10.75 eV
I₁ (eV) = 10.45 eV
Since ;
∴
Hence; the 1st ionization energy of Hg atom =
Finally;