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Thepotemich [5.8K]
4 years ago
13

If a racecar traveling at 6 m/s accelerates at 0.75 m/s over 30 seconds, what is its

Physics
1 answer:
Elina [12.6K]4 years ago
8 0

Answer:

The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.

Explanation:

The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.

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A ball with a mass of 2.89 kg bounces off of the ground. Just before it hits the ground, its velocity is 6.00 m/s in the downwar
White raven [17]

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30.46 kgm/s

Explanation:

According to conservation law of momentum, the magnitude of the impulse J that the ground gave the ball equals to the change in momentum of the ball before and after it hits the ground.

Before the hit, the ball velocity is 6m/s, so its momentum is 6 * 2.89 = 17.34 kgm/s

After the hit, the ball velocity is -4.54 m/s in the opposite direction, so its momentum is 2.89*(-4.54) = -13.12 kgm/s

So the change of momentum, and also the impulse is

17.34 - (-13.12) = 30.46 kgm/s

3 0
3 years ago
you are traveling in a convertible with the top down. the car is moving at a constant velocty of 25 m/s due east along falt grou
velikii [3]

Answer:

Teh velocity of ball with respect to the ground is 29.2 m/s.

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Velocity of car, vc = 25 due m/s east

velocity of ball with respect to car, v(b,c) = 15 m/s due Z axis

Write the velocities in the vector form

\overrightarrow{v}_{c}=25 \widehat{i}\\\\\overrightarrow{v}_{(b,c)}=15 \widehat{k}

The velocity of ball with respect to ground is

\overrightarrow{v}_{(b,c)}= \overrightarrow{v}_{(b,g)}-\overrightarrow{v}_{(c,g)}\\\\15 \widehat{k} = \overrightarrow{v}_{(b,g)} - 25 \widehat{i}\\\\\overrightarrow{v}_{(b,g)} = 25 \widehat{i} + 15 \widehat{k}\\\\v_{(b,g)}=\sqrt{25^2 + 15^2}=29.2 m/s

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3 years ago
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