If a racecar traveling at 6 m/s accelerates at 0.75 m/s over 30 seconds, what is its

Physics

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.

Explanation:

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A class of students performed the heat transfer experiment shown in the picture. In the experiment, three plastic dishes were pa

balandron [24]

The method of heat transfer used in the experiment is radiation.

Radiation is a method of heat transfer in which there is no material medium that conveys heat. Heat travels through empty space and causes the temperature of objects to rise.

In this case, there was no material medium that conveyed heat from the lamp to the dishes containing the plants. Heat from the lamp traveled through space and reached the dishes. This is an example of heat transfer via radiation.

Learn more: brainly.com/question/12494464

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3 years ago

(a) calculate the speed of a proton after it accelerates from rest through a potential difference of 215 v. m/s (b) calculate th

bija089 [108]

<span>The proton differs from the electron in sign although they have the same value. Like the electron, a proton will gain 215 electron-volts of eV in Kinetic energy. So 1.602Ă—10^-19 J * 215 = 344.43 * 10^(-19) J. But K. E. = mv^2 / 2, so v^2 = 2 * K.E/m. The mass of a proton is 1.673 * 10^-27 kg. So v = âš(2 * 344.43 * 10^(-19))/1.673Ă—10^-27 = 688.86 * 10^(-19)/1.673Ă—10^(-27) = 411.75 * 10^(-19-(-27)) = âš411.75 * 10^(8) = 202196.56 Also for the electron we have v^2 = 2 * K.E/m but here mass, m, = 9.109 * 10^-31 kg. So we have v = âš(2 * 344.43 * 10^(-19)) / 9.109 * 10^-31 = 688.86 * 10^(-19)/ 9.109 * 10^-31 = 75.624 * 10^(-19 - (-31)) = 75.624 * 10^(21) and v = 2.749 * 10^11</span>

3 0

3 years ago

An isolated conductor has a net charge of +12.0 × 10- 6 c and a cavity with a particle of charge q = +3.70 × 10-6

pychu [463]

This is just a simple problem finding out the outer surface charge, the inner surface charge and the net charge. Net charge by definition means the difference between two charges. In this case, the formula that is applicable here is outer surface charge = total net charge - inner cavity surface charge. Since we are given already with the net charge equal to 12.0 x10-6 C and the inner charge magnituude f 3.7 x10-6 C, the the total charge must be outer charge is +10x10(-6)) - (-3.0x10(-6)) = +1.3x10(-5) C.
Charges are measured in coloumbs and most likely exist on surfaces of entities like particles, walls etc.

8 0

3 years ago

The rate which light flows through a given area of space is referred to as ita

Brilliant_brown [7]

Hey there!

The correct answer to your question is: Intensity

The rate which light flows through a given area of space is referred to as its intensity. I<span>ntensity and wavelength are two factors which contribute to light energy.</span>
Thank you!

7 0

3 years ago

A transverse wave on a string is described by the following wave function.y = (0.090 m) sin (px/11 + 4pt)(a) Determine the trans

alukav5142 [94]

Explanation:

(a) It is known that equation for transverse wave is given as follows.

y = $(0.09 m)sin(\pi \frac{x}{11} + 4 \pi t)$