Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find:

Answer:
1.25kg
Explanation:
Simply multiply volume and density together
Answer:
1.F = 256 N
2.a = 8 m/s/s
By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.
F = ma
256 N = m * 8 m/s/s
m = 256 N/8 m/s/s
m = 32 Kg
No, and no. In fact, the consequences are exactly opposite to your description.
When you drop soap on the ground, the soap ... which had been clean ... gets dirty, and the ground ... which had been dirty ... gets clean.