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3 years ago

How is taring accomplished?

Physics

1 answer:

attashe74 [19]3 years ago

8 0

Answer:

by taring a balance the process of weighing by difference is done automatically. When a balance is tared with an object, on the balance pan, the weight of the object will be automatically subtracted from reading until the balance is re-tared or zeroed

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How many neutrons does the most common isotope of hydrogen have?

kipiarov [429]

The most common hydrogen isotope, protium, has no neutrons in the nucleus.

Isotopes of

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3 years ago

What is the frequency of an X-ray with wavelength 0.13 nm ? Assume that the wave travels in free space. Express your answer to t

dem82 [27]

Answer:

Frequency, $f=2.30\times 10^{18}\ Hz$

Explanation:

Given that,

The wavelength of the x-rays, $\lambda=0.13\ nm=0.13\times 10^{-9}\ m$

We need to find the frequency of an x-ray. All electromagnetic wave travel with a speed of light. It is given by the formula as :

$c=f\lambda$

f is the frequency

$f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz$

So, the frequency of an x-ray is $2.30\times 10^{18}\ Hz$ . Hence, this is the required solution.

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3 years ago

Hair color is a trait that’s controlled by many genes working together. Each gene contributes to this trait only in a small prop

Katena32 [7]

Codominence i think, its both parents genes are used

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3 years ago

Two convex lenses are placed 15 cm apart. The left lens has a focal length of 10 cm, and the right lens a focal length of 5 cm.

Minchanka [31]

Answer:

The image distance from right lens is 2.86 cm and image is real.

Explanation:

Given that,

Focal length of left lens = 10 cm

Focal length of right lens = 5 cm

Distance between the lenses d= 15 cm

Object distance = 50 cm

We need to calculate the image distance from left lens

Using formula of lens

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-50}$

$\dfrac{1}{v}=\dfrac{3}{25}$

$v=8.33\ cm$

We need to calculate the image distance from right lens

The object distance will be

$u = 15-8.33 = 6.67\ cm$

Using formula of lens

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{5}-\dfrac{1}{-6.67}$

$\dfrac{1}{v}=\dfrac{1167}{3335}$

$v=2.86\ cm$

The image is real.

Hence, The image distance from right lens is 2.86 cm and image is real.

4 0

3 years ago

A ball rolls downhill with a constant acceleration of 4m/s squared. If it started from rest,it’s velocity at the end of 3 meters

vladimir2022 [97]

Answer:

4.9 m/s

Explanation:

Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the ball in this problem,

u = 0 (it starts from rest)

$a=4 m/s^2$ is the acceleration

s = 3 m is the distance covered

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(4)(3)}=4.9 m/s$

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3 years ago