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SSSSS [86.1K]
3 years ago
13

A satellite orbiting earth once per day. From the reference frame of the moon, which orbit Earth once about every 27 days, what

is its motion?
A.The satellite never moves relative to the moon
B.The satellite travels continuously away from the moon.
C. The satellite remains at a constant distance from the moon.
D.The satellite continuously move closer and farther away from the mood.
Physics
2 answers:
sineoko [7]3 years ago
7 0
If each day the satelite orbits the earth its going faster than the moon and is passing it, so the satellite continuously moves closer and further away from the moon. like if you were standing watching a race then the racers would be moving away then towards you then away again
egoroff_w [7]3 years ago
6 0

Answer: D.The satellite continuously move closer and farther away from the moon.

The moon rotates on its axis and revolves around Earth in 27 days. The satellite is orbiting Earth once per day.

In moon 's frame of reference, the satellite would be in motion. Sometime it would be away and sometimes closer. From moon, we would observe satellite to rotate about the Earth. The satellite would get eclipsed by the Earth sometimes when it would go behind it as viewed from moon.

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The transfer of energy when particles of a fluid move from one place to another is called
siniylev [52]

Answer:

Answer below!!!!

Explanation:

Convection is the transfer of thermal energy by particles moving through a fluid.

Hope I Helped!!!

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5 0
3 years ago
The components of a 10.8-meters-per-second velocity at an angle of 34.° above the horizontal are
Kisachek [45]

Answer:

6.0 m/s vertical and 9.0 m/s horizontal

Explanation:

For the vertical component, we use the formula:

  • Sin(34°) = <em>y</em> / 10.8

Then we <u>solve for </u><u><em>y</em></u>:

  • 0.559 = <em>y</em> / 10.8
  • <em>y </em>= 6.0

And for the horizontal component, we use the formula:

  • Cos(34°) = <em>x</em> / 10.8

Then we <u>solve for </u><u><em>x</em></u><u>:</u>

  • 0.829 = <em>x</em> / 10.8
  • <em>y </em>= 9.0

So the answer is " 6.0 m/s vertical and 9.0 m/s horizontal".

3 0
3 years ago
what will the stopping distance be a a 3000-kg car if -3000N of force are applied when the car is traveling 10 m/s
Inga [223]

Answer:

50 m

Explanation:

Acceleration= force/mass

3000/3000=1m/s^-2

Applying equation of motion:

V^2=U^2+2as; V is final velocity, u is initial velocity, a is acceleration and s is the distance covered.

0=10^2 -2*1s;

Solve for s

5 0
4 years ago
A car travels across Texas m miles at the rate of t miles per hour. How many hours does the trip take??
Marianna [84]

Answer: The trip takes \frac{m}{t}hours

Explanation:

Velocity V is the variation of the position of a body (distance traveled d) with time T:

V=\frac{d}{T}

In this case, the car travels a distance d=m miles at a velocity V=t \frac{miles}{hour} and we need to find the time it takes the trip.

Isolating  T:

T=\frac{d}{V}=\frac{m miles}{t \frac{miles}{hour}}

Finally:

T=\frac{m}{t}hours

8 0
3 years ago
A bus slows with constant acceleration from 24.0 m/s to 16.0 m/s and moves 50.0 m in the process. (a) How much further does it t
navik [9.2K]

Answer:

(a) Bus will traveled further a distance of 40 m

(b) It will take 7.5 sec to stop the bus

Explanation:

We have given initial velocity of the bus u = 24 m/sec

And final velocity v = 16 m/sec

Distance traveled in this process s = 50 m

From third equation of motion we know that v^2=u^2+2as

16^2=24^2+2\times a\times 50

a=-3.2m/sec^2

(a) Now as the bus finally stops so final velocity v = 0 m/sec

So v^2=u^2+2as

0^2=24^2-2\times 3.2\times s

s= 90 m

So further distance traveled by bus = 90-50 =40 m

(b) Now as the bus finally stops so final velocity v= 0 m/sec

Initial velocity u = 24 m/sec

Acceleration a=-3.2m/sec^2

So time t=\frac{v-u}{a}=\frac{0-24}{-3.2}=7.5sec

7 0
3 years ago
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