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SSSSS [86.1K]
3 years ago
13

A satellite orbiting earth once per day. From the reference frame of the moon, which orbit Earth once about every 27 days, what

is its motion?
A.The satellite never moves relative to the moon
B.The satellite travels continuously away from the moon.
C. The satellite remains at a constant distance from the moon.
D.The satellite continuously move closer and farther away from the mood.
Physics
2 answers:
sineoko [7]3 years ago
7 0
If each day the satelite orbits the earth its going faster than the moon and is passing it, so the satellite continuously moves closer and further away from the moon. like if you were standing watching a race then the racers would be moving away then towards you then away again
egoroff_w [7]3 years ago
6 0

Answer: D.The satellite continuously move closer and farther away from the moon.

The moon rotates on its axis and revolves around Earth in 27 days. The satellite is orbiting Earth once per day.

In moon 's frame of reference, the satellite would be in motion. Sometime it would be away and sometimes closer. From moon, we would observe satellite to rotate about the Earth. The satellite would get eclipsed by the Earth sometimes when it would go behind it as viewed from moon.

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A mixture in which the parts can be seen separately from the other parts is considered to be what type of mixture
serious [3.7K]

Answer: A mixture is a combination of two or more substances (elements or compounds) which is not done chemically. Mixtures are two types Homogeneous Mixtures and Heterogeneous mixtures.

6 0
3 years ago
What is the maximum value of the magnetic field at a distance of 2.5 m from a light bulb that radiates 100 W of single-frequency
Anvisha [2.4K]

Answer:

1.04\times 10^{-7} T

Explanation:

IP  = Power of the bulb = 100 W

r  = distance from the bulb = 2.5 m

I = Intensity of light at the location

Intensity of the light at the location is given as

I = \frac{P}{4\pi r^{2}}

I = \frac{100}{4(3.14) (2.5)^{2}}

I = 1.28 W/m²

B_{o} = maximum magnetic field

Intensity is given as

I = \frac{B_{o}^{2}c}{2\mu _{o}}

1.28 = \frac{B_{o}^{2}(3\times 10^{8})}{2(12.56\times 10^{-7})}

B_{o} = 1.04\times 10^{-7} T

7 0
3 years ago
Explain how potential difference produces a current in a conductor.
Yuki888 [10]
Potential difference is the work done In moving a charge from one point to another in a conductor
5 0
3 years ago
Calculate the energy, wavelength, and frequency of the emitted photon when an electron moves from an energy level of -3.40 eV to
jasenka [17]

Answer:

(a) The energy of the photon is 1.632 x 10^{-8} J.

(b) The wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency of the photon is 2.47 x 10^{25} Hz.

Explanation:

Let;

E_{1} = -13.60 ev

E_{2} = -3.40 ev

(a) Energy of the emitted photon can be determined as;

E_{2} - E_{1} = -3.40 - (-13.60)

           = -3.40 + 13.60

           = 10.20 eV

           = 10.20(1.6 x 10^{-9})

E_{2} - E_{1} = 1.632 x 10^{-8} Joules

The energy of the emitted photon is 10.20 eV (or 1.632 x 10^{-8} Joules).

(b) The wavelength, λ, can be determined as;

E = (hc)/ λ

where: E is the energy of the photon, h is the Planck's constant (6.6 x 10^{-34} Js), c is the speed of light (3 x 10^{8} m/s) and λ is the wavelength.

10.20(1.6 x 10^{-9}) = (6.6 x 10^{-34} * 3 x 10^{8})/ λ

λ = \frac{1.98*10^{-25} }{1.632*10^{-8} }

  = 1.213 x 10^{-17}

Wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency can be determined by;

E = hf

where f is the frequency of the photon.

1.632 x 10^{-8}  = 6.6 x 10^{-34} x f

f = \frac{1.632*10^{-8} }{6.6*10^{-34} }

 = 2.47 x 10^{25} Hz

Frequency of the emitted photon is 2.47 x 10^{25} Hz.

6 0
2 years ago
Which type of employee would most likely spend the majority of work time in a vehicle? O a Corrections Officer at a jail O a Dis
dsp73

Answer:

Paramedic

Explanation:

They will be on the move the whole time

8 0
3 years ago
Read 2 more answers
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