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borishaifa [10]
3 years ago
8

the gasoline in a car does 40000 j of work on a car and generates a constant force of 20 n. how far did the car go?

Physics
1 answer:
NikAS [45]3 years ago
8 0

     Work  =  (force) x (distance)

     40,000 J  =  (20 N) x (distance)

     Distance  =  (40,000 J) / (20 N)

                    =    2,000 meters

                    =     2 kilometers.

(20 N is not a huge force when it's being used to move a car.
It's only about  4.5 pounds.) 
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puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

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In order to place a satellite into orbit, it requires enough fuel to supply the necessary mechanical energy. Into what types of
nexus9112 [7]

When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

F_g = F_c

\frac{GM_pM_s}{r^2} = \frac{M_s v^2}{r}

now we can say that kinetic energy of satellite is  given as

KE = \frac{1}{2}M_s v^2

KE = \frac{GM_sM_p}{2r}

also we know that since satellite is in gravitational field of the planet so here it must have some gravitational potential energy in it

so we will have

U = -\frac{GM_sM_p}{r}

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6 0
3 years ago
If an astronaut throws an object in space, the object’s speed will _____
BigorU [14]
The object's speed will not change.

In fact, after the astronaut throws the object, no additional forces will act on it (since the object is in free space). According to Newton's second law:
\sum F=ma
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A boy and a girl are on a spinning merry-go-round. The boy is at a radial distance of 1.2 m from the central axis; the girl is a
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Answer:

E) True. The girl has a larger tangential acceleration than the boy.

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In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.

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as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different

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whereby

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reviewing the claims we have

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          a₂ = α 1.8

          a₂> a₁

A) False. Tangential velocity is different from zero

B) False angular acceleration is the same for both

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D) False. Angular acceleration is equal

E) True. You agree with the analysis above,

8 0
2 years ago
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