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lilavasa [31]
3 years ago
5

Which numbers are shown in the symbol for a radioactive nuclide?

Chemistry
2 answers:
stira [4]3 years ago
7 0

Answer:

The answer is C.

"The atomic number and mass number."

Explanation:

Got it right on Edge!

Have a good day!

Y_Kistochka [10]3 years ago
4 0

Answer:

C

Explanation:

edge

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What property of water is primary for living organisms? (SC.6.E.7.4) *
katrin [286]

Answer:

It is liquid at most temperatures on Earth.

8 0
3 years ago
An aqueous solution of sodium fluoride is slowly added to a water sample that contains barium ion (2.75×10-2M ) and calcium ion
Alona [7]

Answer : The remaining concentration of the first ion to precipitate when the second ion begins to precipitate is, 1.07\times 10^{-6}M

Explanation :

The dissociation of barium fluoride is written as:

BaF_2\rightleftharpoons Ba^{2+}+2F^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ba^{2+}][F^-]^2

As we know that at room temperature 25^oC the K_{sp} of barium fluoride is, 1\times 10^{-6}.

Now put all the given values in this expression, we get:

1\times 10^{-6}=(2.75\times 10^{-2})\times [F^-]^2

[F^-]=6.03\times 10^{-3}M=0.00603M

The barium fluoride precipitate when fluoride ion is equal to 0.00603 M.

The dissociation of calcium fluoride is written as:

CaF_2\rightleftharpoons Ca^{2+}+2F^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][F^-]^2

As we know that at room temperature 25^oC the K_{sp} of calcium fluoride is, 3.90\times 10^{-11}.

Now put all the given values in this expression, we get:

3.90\times 10^{-11}=(6.70\times 10^{-2})\times [F^-]^2

[F^-]=2.41\times 10^{-5}M=0.0000241M

The calcium fluoride precipitate when fluoride ion is equal to 0.0000241 M.

Since, the fluoride ion concentration in calcium fluoride is less then the fluoride ion concentration in barium fluoride. That means, calcium fluoride will precipitate first.

Thus, the concentration Ca^{2+} ion remaining at F^- concentration (0.00603 M) is calculated as:

K_{sp}=[Ca^{2+}][F^-]^2

Now put all the given values in this expression, we get:

3.90\times 10^{-11}=[Ca^{2+}]\times (0.00603)^2

[Ca^{2+}]=1.07\times 10^{-6}M

Therefore, the remaining concentration of the first ion to precipitate when the second ion begins to precipitate is, 1.07\times 10^{-6}M

3 0
3 years ago
What is the formula for barium iodide?
zysi [14]
Formula :  BaI₂. <span>barium iodide</span>
6 0
3 years ago
What is ph and how does it measure the concentration of acids and bases?
Lilit [14]
PH is what they call measure of the concentration<span> of hydrogen ions in a solution. Strong </span>acids <span>like hydrochloric </span>acid<span> at the sort of </span>concentrations<span> you normally use in the lab have a pH around 0 to 1. The lower the pH, the higher the </span>concentration<span> of hydrogen ions in the solution. </span>
7 0
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How many grams of hydrogen are necessary to react with 2.85 mol CO
Lynna [10]

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6 0
3 years ago
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