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-BARSIC- [3]
2 years ago
7

Stock bottles should be moved on the shelves A. by placing new stock behind old stock so stock closest to expiration gets used f

irst. B. from left to right in alphabetical order. C. by placing new stock in front of old stock so the freshest is used first. D. from left to right in numeric order based on the NDC.
Mathematics
1 answer:
Vinvika [58]2 years ago
6 0
A. By placing new stock behind old stock
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verify that the fucntion satisfies the three hypotheses of rolles theorem on the given interval . then find all numbers c that s
Ghella [55]

The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:

<span><span>x1 </span>= 0.42801</span>

<span><span>x2 </span>= −1.51414</span>

<span><span>x3 </span>= 3.08613</span>


x1 and x2 are in the desired interval [-2, 2]

f'(x) = 3x^2 - 4x - 4

so we have:

3x^2 - 4x - 4 = 0

<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6

x_1 = -4/6 = -0.66

x_ 2 = 2

According to Rolle's theorem, we have one point in between:

x1 = 0.42801 and x2 = −1.51414

where f'(x) = 0, and that is <span>x_1 = -0.66</span>

so we see that Rolle's theorem holds in our function.

4 0
3 years ago
1/2 - 1/5= ???
Aleonysh [2.5K]
Stop asking questons we are pretty much telling you the answer figure it out your self
6 0
3 years ago
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Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a
Maslowich

Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

The correct statement would be:

"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"

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2 years ago
A ray that contains a point that is equidistant from both sides of the angle. *
seraphim [82]
<span>Consider a angle â BAC and the point D on its defector Assume that DB is perpendicular to AB and DC is perpendicular to AC. Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC Proof Consider triangles ΔADB and ΔADC Both are right angle, â ABD= â ACD=90 degree They have congruent acute angle â BAD and â CAD( since AD is angle bisector) They share hypotenuse AD therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
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3 years ago
Write the following integers in a decreasing order. 1. 0,7,-3,9,-132,36​
Elan Coil [88]
ANSWER:
36 > 9 > 7 > 0 > -3 > -132

Hope it helps u!
6 0
3 years ago
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