What is the value of the underlined digit 28

If 5 , 3 = 28 9 , 1 = 810 8 , 7 = 115 6 , 2 = 48 then 7 , 5 = ?

Rom4ik [11]

Answer:

212

Step-by-step explanation:

Rule

Subtract the 2nd number from the first to obtain the first digit(s) of the answer.
Add the 2nd number to the 1st to obtain the last digit(s) of the answer.

5 - 3 = 2

5 + 3 = 8

Therefore: 28

9 - 1 = 8

9 + 1 = 10

Therefore: 810

8 - 7 = 1

8 + 7 = 15

Therefore: 115

6 - 2 = 4

6 + 2 = 8

Therefore: 48

7 - 5 = 2

7 + 5 = 12

Therefore: 212

6 0

2 years ago

Read 2 more answers

Calculate the determinant of this matrix step 1: what is the first step

bagirrra123 [75]

Answer:

Step 1: Rewrite the first two columns of the matrix.

Step 2: Multiply diagonally downward and diagonally upward.

Step 3: Add the downward numbers together.

Step 4: Add the upward numbers together.

Step-by-step explanation:

hope this helps ;)

7 0

2 years ago

Read 2 more answers

The weather forecast warns of morning fog today. you may only be able to see 0.6 mile in front of you. how many feet is this?

Kamila [148]

This a problem of conversion of units. to convert units, you must know at what values are each units equal. for this problem we must convert miles to feet. so 1 mile is equivalent to 5280 ft. so the answer is :
length in feet = 0.6 miles ( 5280 ft / 1 mile)
length in feet = 3168 feet

4 0

3 years ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

A map using a scale inch of 1 to 5 miles shows a section of land with an area of 3.2 in.² what is the actual area of the section

Karolina [17]

Answer:

The actual area of land is 80 mi² .

Step-by-step explanation:

Given that we have to find the actual area so first we have to square the ratio(scale factor) :

1 in : 5 mi

(1 in)² : (5 mi)²

1 in² : 25 mi²

Next, the actual area will be :

1 in² = 25 mi²

(1 × 3.2) in² = (25 × 3.2) mi²

3.2 in² = 80 mi²

6 0

3 years ago