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Arte-miy333 [17]
2 years ago
8

A student developed a chromatogram and found that the cluent front traveled 94 mm and the Zn²+ cation traveled

Chemistry
1 answer:
Valentin [98]2 years ago
4 0

Answer:

srry i can't answer that

Explanation:

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Số hợp chất tố đa của nguyên tố này với nguyên tố khác theo hóa trị của nó
SVETLANKA909090 [29]

Answer:

Carbon

Explanation:

Carbon

5 0
3 years ago
A sample of 1L of gas in a container at-73C has a pressure of 32.2inHg. To
Goryan [66]

Answer:

Like you, like you

Like you, ooh

I found it hard to find someone like you

Like you, like you

Send your location, come through

I can't sleep no more

In my head, we belong

And I can't be without you

Why can't I find no one like you?

I can't sleep no more

In my head, we belong

And I can't be without you

Why can't I find no one like you?

Explanation:

8 0
3 years ago
An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average
Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = \frac{Displacement }{Change in time} = Δx / Δt = \frac{x2 - x1}{t2 - t1}

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{2100km }{1000km/h}

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{1300km }{800km/h}

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = \frac{x2 - x1}{t2 - t1}

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = \frac{1300 - 2100}{1.625 - 2.1}

Average velocity = 1684.21 km/h

7 0
3 years ago
Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.
Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) <u>Trypsin</u>

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) <u>Chymotrypsin</u>

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the <u>"Lis"</u> and <u>"Arg"</u> (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the <u>"Phe"</u> (See figure 2). The second amino acid that can be broken is <u>tyrosine</u>, but this amino acid is placed in the <u>C terminal spot</u>, therefore will not be involved in the <u>hydrolysis</u>.

3 0
3 years ago
Va rog urgent e pt chimie​
den301095 [7]

Answer:

It conducts electricity

It conducts heat

Water is needed for rusting

Explanation:

Metals refer to elements that are found towards the left hand side of the periodic table of elements. They are found in groups 1- 13 and few of them are also found at the bottom of groups 14 and 15.

Now these metal have certain properties that are general to all of them. two of these properties listed among the options in the question are;

i) They conduct electricity

ii) They conduct heat

These properties apply to all metals universally.

Rusting is an electrochemical reaction in which hydrated iron III oxide is formed. In the electrochemical reaction, water in intimately involved in the process. Hence; oxygen and water are required for rusting to take place.

8 0
3 years ago
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